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Ilya [14]
3 years ago
14

Jane orders cheese pizza from a pizza restaurant that charges $8 per pizza , Jane cost, in dollars, is a function of the numbers

of pizza she orders , in the context of this story what does the domain and range represents and how do you know?,

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0

search des mos on goo gle click graphing calculator type in the equation y =-8x+45 and then copy the graph, I suggest doing one digits and also you didn't send the full question

She can get 5 pizzas using all her money

Finding Maxmium She Can Get

8.00*n ≤ 45.00

n ≤ 45/8 = 5.625

Jane can order at most 5 pizzas.

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In a recent study, researchers found that 31 out of 150 boys aged 7-13 were overweight or obese. On the basis of this study can
AURORKA [14]

Answer:

1) Null hypothesis:p \leq 0.15  

Alternative hypothesis:p > 0.15  

2) The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) z_{crit}= 1.64

And the rejection zone would be z>1.64

4) Calculate the statistic  

z=\frac{0.207 -0.15}{\sqrt{\frac{0.15(1-0.15)}{150}}}=1.955  

5) Statistical decision  

For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=21 represent the boys overweight

\hat p=\frac{31}{150}=0.207 estimated proportion of boy overweigth

p_o=0.15 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

1) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the true proportion of boys obese is higher than 0.15.:  

Null hypothesis:p \leq 0.15  

Alternative hypothesis:p > 0.15  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

2) The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Decision rule

For this case we need a value on the normal standard distribution who accumulates 0.05 of the area on the right tail and on this case this value is:

z_{crit}= 1.64

And the rejection zone would be z>1.64

4) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.207 -0.15}{\sqrt{\frac{0.15(1-0.15)}{150}}}=1.955  

5) Statistical decision  

For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15

6 0
3 years ago
Find the other end point<br> Endpoint (5,-1) Midpoint (5,10)
dusya [7]

Answer:

(5, 21)

Step-by-step explanation:

The x-coordinate of the midpoint of a segment is half of the sum of the x-coordinates of the endpoints.

The y-coordinate of the midpoint of a segment is half of the sum of the y-coordinates of the endpoints.

Let the unknown point have coordinates (x, y).

x-coordinate:

(5 + x)/2 = 5

5 + x = 10

x = 5

y-coordinate:

(-1 + y)/2 = 10

-1 + y = 20

y = 21

The other endpoint has coordinates (5, 21).

8 0
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Answer:

B.) -4

Step-by-step explanation:

y=mx+b

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Answer:

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Step-by-step explanation:

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Answer:

Quinzel sold 17 pairs of shoes last month.

Step-by-step explanation:

Let be "Q" the number of pairs of shoes Quinzel sold last month and "J" the number of pairs of shoes Joseph sold last month.

Set up a system of equations:

\left \{ {{Q=J-18} \atop {Q+J=52} \right.

Solve for "J" from the first equation:

J=Q+18

Applying the Substitution Method, you get:

Q+J=52\\\\Q+(Q+18)=52\\\\2Q=52-18\\\\Q=\frac{34}{2} \\\\Q=17

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