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lozanna [386]
3 years ago
14

3x + 2y = 5

Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

I am guessing the 1st one.

Step-by-step explanation:

8x does NOT equal 12 I believe. I am sorry if I am incorrect

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What is the measure of AngleDCF? Three lines extend from point C. The space between line C D and C E is 75 degrees. The space be
gizmo_the_mogwai [7]

Answer:

  ∠DCF = 129°

Step-by-step explanation:

We assume that line CE is between lines CD and CF.

The angle sum theorem applies:

  ∠DCF = ∠DCE +∠ECF

  ∠DCF = 75° +54°

  ∠DCF = 129°

4 0
4 years ago
Read 2 more answers
Oel is laying pipe for a sprinkler system before he plants his lawn. the lawn is a rectangle, 15 feet long and 8 feet wide. he n
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The Pythagorean theorem tells you that length is
.. √(15^2 +8^2) = 17 . . . feet
4 0
3 years ago
Can I get some help on these two question im confused
Sedbober [7]

Answer:

for 1 I am guessing D and for 2 I am guessing B.

5 0
3 years ago
If UT is a midsegment of QRS, find SQ<br> A. 8 <br> B. 10 <br> C. 16 <br> D. 20
sladkih [1.3K]
If UT is the midsegment of QRS, then SQ = 2(2x + 2) = 4x + 4
Then,
(3x + 1)/(7x - 1) = (2x + 2)/(4x + 4) = 1/2
2(3x + 1) = 7x - 1
6x + 2 = 7x - 1
7x - 6x = 2 + 1
x = 3

Therefore, SQ = 4(3) + 4 = 12 + 4 = 16.
8 0
3 years ago
a swim meet has 13 contestants . the first heat has 6 simmers . how many different ways can the contestants be arranged in the f
yawa3891 [41]
Answer: 1, 235, 520 different arrangements
Explanation: Since we want to arrange them, we care about the order in which they come in.
Let's firstly think about it in a diagrammatic way before diving into the permutations side of things.

We have 13 swimmers, let's name them from 1 to 13. Now, we want to arrange six of them in a line (hypothetically).

Thus, we can arrange the first six people:

1 2 3 4 5 6
1 2 3 4 6 5
1 2 3 6 5 4
1 2 3 6 4 5
...

In fact, we have 6! ways in arranging six objects into six places, which is 720 different ways.

Now, let's think about it in a bigger spectrum. If we have 13 people and we want to arrange them in 13 blocks, we would have 13! ways in arranging them:

Different permutations:
Ways in arranging 13 people into 13 different lanes is given by: 13!
Now, we want to restrict that into 6 blocks, so we can only have 6 people in it
So, we would have (13 - 6)! ways in arranging them into 6 blocks.

So, our final number of arrangements is: \frac{13!}{(13 - 6)!} = 1 235 520 ways.

This is also the formula for the Permutation function represented by: ^{n}P_r, where n is the number of objects (13) and r is the number of positions (6). 
5 0
3 years ago
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