I don't see a table but I can give you the means to answer it yourself. The inverse function is represented by this: $y= \frac{k}{x}$ where k is your constant. You are given a k value of 4. If you solve this for k then you will get xy=4. In your tables, multiply your x value by your y value within your coordinate points and if you get a product of 4 each time you multiply x by y, then that table is your answer.

8 0

3 years ago

Which equation represents the circle described? (in picture)

Sedaia [141]

You are right. In circle equation we have =r² so the correct answer will be C od D. But we have to calculate the center of a circle.

$x^2+y^2-8x-6y+24=0\quad|-24\\\\(x^2-8x)+(y^2-6y)=-24$

Complete the square:

$x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2$

And we have:

$(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\
(x-4)^2+(y-3)^2-16-9=-24\\\\(x-4)^2+(y-3)^2-25=-24\quad|+25\\\\\boxed{(x-4)^2+(y-3)^2=1}$

So the answer is C (the same left side of equation).

6 0

3 years ago

Find the product of the monomial and the polynomial. 4a^2b^3*(9a^4b^2-4a^2+3)

Artemon [7]

Answer:

Step-by-step explanation:

4a² b³ * (9a⁴b² - 4a² + 3) = 4a²b³ * 9a⁴b² - 4a²b³*4a² + 4a²b³*3

= 36a²⁺⁴ b³⁺² -16a²⁺²b³ + 12a²b³

= 36a⁶b⁵ - 16a⁴b³ + 12a²b³

6 0

3 years ago