3,503,832.97 hope this helps! :)
Answer: 1,665.98
Step-by-step explanation: Use the equation
:)
No. of students playing at least one game = 44
Step-by-step explanation:
B = basketball; V = volleyball
n(B) = no of students playing only B
n(V) = no. of students playing only V
n(B∩V) = no. of students playing both B and V
Now:
32 students play basketball. Some of them could also be playing volleyball. Hence, the number of students playing only basketball will be 32 minus those that play both.
n(B) = 32 - 13 ............(Given that 13 play both games)
n(B) = 19
Similarly,
25 students play volleyball. Some of them could also be playing basketball. Hence, the number of students playing only volleyball will be 25 minus those that play both.
n(V) = 25 - 13
n(V) = 12
Thus, we have 19 students playing only B, 12 students playing only V and 13 students playing BOTH.
Clearly, the number of students that play at least one game is:
No. of students playing ONLY basketball +
No. of students playing ONLY volleyball +
No. of students playing BOTH
This can be given as:
n(B) + n(V) + n(B∩V)
= 19 + 12 + 13
= 44
Answer:
Option A
Step-by-step explanation:
You're welcome.
Answer:
value of x = 4
Step-by-step explanation:
here's the solution : -
=》6 - 2x = 5x - 9x + 8
shifting like terms aside,
=》6 - 8 = 5x - 9x + 2x
\_(●_●)_/
=》-2 = -2x
=》x = -2 / -2
=》x = 1