We know that , in a circle radius perpendicular to chord will bisect the chord.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer:
C. Either positive or negative
Let's solve your inequality step-by-step.
<span><span><span>
a − 8 </span>+ 15 </span>> <span>23
</span></span>Step 1: Simplify both sides of the inequality.
<span><span><span><span><span>
−1/</span>8</span>a </span>+ 15 </span>> 23
</span>
Step 2: Subtract 15 from both sides.
<span><span><span><span><span><span>
−1/</span>8</span>a </span>+ 15 </span>− 15 </span>> <span>23 − 15
</span></span><span><span><span><span>
−1/</span>8</span>a </span>> 8
</span>
Step 3: Multiply both sides by 8/(-1).
<span><span><span>
(<span>8/<span>−1</span></span>) </span>* <span>(<span><span><span>−1/</span>8</span>a</span>) </span></span>> <span><span>(<span>8/<span>−1</span></span>) </span>* <span>(8)
</span></span></span><span>
a < <span>−<span>64
Therefore, the answer is a < -64! I hope this helped! :)</span></span></span>
Answer:
C
Step-by-step explanation:
The length of arc AC (L) is calculated as
L = circumference of circle × fraction of circle
= 2πr × 
= 2π × 12 × 
= 2π × 5
= 10π ≈ 31.42 → C
So the ratios are 5:5 and 3:5 so the fractions are 5/10 (1/2) for 7th grade and 5/8 for 8th grade
