The cube root is 10 bc 10x10x10 = 100
Both trains travel for 7 time units.
Train A travels 385 distance units, so its speed is
Train B travels 577.5 distance units, so its speed is
Note that the units are not specified, but considering that we're talking about trains, the graph is likely to be showing distance in km (or miles) and time in hours.
Also, the distance traveled by train B is not perfectly aligned with the grid, so I assumed that it was the average between the two ticks of 550 and 605.
It's just 24.53 because the hundredth place is the 3, but the value after it is not high enough to round it up. Therefore, the answer is 24.53
1 Convert 12\frac{2}{3}12
3
2
to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a
c
b
=
c
ac+b
\frac{12\times 3+2}{3}\times 3\frac{1}{4}
3
12×3+2
×3
4
1
2 Simplify 12\times 312×3 to 3636
\frac{36+2}{3}\times 3\frac{1}{4}
3
36+2
×3
4
1
3 Simplify 36+236+2 to 3838
\frac{38}{3}\times 3\frac{1}{4}
3
38
×3
4
1
4 Convert 3\frac{1}{4}3
4
1
to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a
c
b
=
c
ac+b
\frac{38}{3}\times \frac{3\times 4+1}{4}
3
38
×
4
3×4+1
5 Simplify 3\times 43×4 to 1212
\frac{38}{3}\times \frac{12+1}{4}
3
38
×
4
12+1
6 Simplify 12+112+1 to 1313
\frac{38}{3}\times \frac{13}{4}
3
38
×
4
13
7 Use this rule: \frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd}
b
a
×
d
c
=
bd
ac
\frac{38\times 13}{3\times 4}
3×4
38×13
8 Simplify 38\times 1338×13 to 494494
\frac{494}{3\times 4}
3×4
494
9 Simplify 3\times 43×4 to 1212
\frac{494}{12}
12
494
10 Simplify
\frac{247}{6}
6
247
11 Convert to mixed fraction
41\frac{1}{6}41
6
1
41 and 1/6
Parking charges for first 2hours =$5 per hour after 2 hours parking charges = $2.50per hour
