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Troyanec [42]
3 years ago
6

Help me plzzzzzzzzzzzzzzzzzzzzzzzz

Mathematics
1 answer:
garik1379 [7]3 years ago
6 0

B. \frac{5}{8}, 2.5, \sqrt{10}

Though ⅝ and 2.5 can be written in form of p/q where p is any real number and q ≠ 0.

But, in case of \sqrt{10}, the decimal expansion of this number is non - terminating, non - repeating.

⇒ This is an irrational number.

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Perimeter of the triangle below ?
Paha777 [63]

Answer:

31x^2-13x

Step-by-step explanation:

to find the perimeter of a triangle, add all sides.

P=a+b+c

P=(5x^2+x)+(8x^2-3x)+(18x^2-11x)

combine like terms

5x^2+8x^2-18x^2= 31x^2

x-3x-11x= -13x

31x^2-13x

5 0
4 years ago
What kind of triangles does the Pythagorean theorem work for?
Tasya [4]

Answer:

A. Right angle traingle Is the answer

5 0
3 years ago
Read 2 more answers
Which expression is equivalent to x2+3x+ 3+ (2x+134+15) - (x+5))
tia_tia [17]

Answer:

x^{2} + ( 4x) + (147)

Step-by-step explanation:

Here, the given expression is

x^{2} +3x +3 + (2x+134+15) - (x+5)

Now, simplifying the brackets, we get

x^{2} +3x +3 + (2x+134+15) - (x+5) = x^{2} +3x +3 + 2x+134+15 - x -5

Now, operate on the like terms.

= x^{2} + ( 3x + 2x -x) + (134 + 15 + 3 -5)

=x^{2} + ( 4x) + (147)

Hence, the given expression is simplified to the quadratic equation x^{2} + ( 4x) + (147)

5 0
3 years ago
What is the value of the expression x^3y^2/6 + x^2y^2 x = -2 and y = 3?
Volgvan

\huge\text{Hey there!}

\mathsf{\dfrac{(-2^3)(3^2)}{6}+(-2^2)(3^2)}

\mathsf{(-2)^3=\bf -8}

\mathsf{= \dfrac{-8(3^2)}{6}+(-2^2)(3^2)}

\mathsf{3^2=\bf 9}

\mathsf{= \dfrac{(-8)(9)}{6}+(-2^2)(3^2)}

\mathsf{-8(9)= \bf -72}

\mathsf{= \dfrac{-72}{6}+(-2^2)+(3^2)}

\mathsf{\dfrac{-72}{6}=\bf -12}

\mathsf{= -12+(-2)^2(3^2)}

\mathsf{-2^2=\bf 4}

\mathsf{= -12+4(3^2)}

\mathsf{3^2=\bf 9}

\mathsf{= -12+4(9)}

\mathsf{4(9)= \bf 36}

\mathsf{-12 + 36 = \bf 24}

\boxed{\boxed{\large\text{Answer: \huge\bf Option C. 24}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

5 0
4 years ago
-5x + 3y = -8<br> 3x - 7y= -3
AnnZ [28]

Answer:

x = 5/2   y = 3/2

Step-by-step explanation:

You need to write what the question is besides the information in the problem.  I assume the question is to find the values of x and y.

Going on that premise, Let equation (1)   be -5x + 3y = -8 and

equation (2)  be 3x - 7y = -3

Lets multiply (1) by 3 and (2) by 5 and we get equations (4) and (5)

(4)   -15x + 9y = -24    and  (5)    15x - 35y = -15  Now add (4) and (5)

-15x + 9y = -24

<u> 15x - 35y = -15</u>

      -26y = - 39

y = 3/2     Now substitute y = 3/2 in equation (1).  -5x + 3)(3/2) = -8

                                                                                 -5x + 9/2 = -8

                                                                                  -10x + 9 = -16

                                                                                  -10x = -25

                                                                                      x = -25/-10 = 5/2  

x = 5/2   y = 3/2

Check:  Substitute your answers into equation (2) and see if they work.

3(5/2) -7(3/2) = 15/2 - 21/2 = -6/2 = -3   Hooray!  We have the correct values for x and y that makes each equation true  

8 0
3 years ago
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