Question

What is the value of the expression x^3y^2/6 + x^2y^2 x = -2 and y = 3?

Answer 1

$\huge\text{Hey there!}$

$\mathsf{\dfrac{(-2^3)(3^2)}{6}+(-2^2)(3^2)}$

$\mathsf{(-2)^3=\bf -8}$

$\mathsf{= \dfrac{-8(3^2)}{6}+(-2^2)(3^2)}$

$\mathsf{3^2=\bf 9}$

$\mathsf{= \dfrac{(-8)(9)}{6}+(-2^2)(3^2)}$

$\mathsf{-8(9)= \bf -72}$

$\mathsf{= \dfrac{-72}{6}+(-2^2)+(3^2)}$

$\mathsf{\dfrac{-72}{6}=\bf -12}$

$\mathsf{= -12+(-2)^2(3^2)}$

$\mathsf{-2^2=\bf 4}$

$\mathsf{= -12+4(3^2)}$

$\mathsf{3^2=\bf 9}$

$\mathsf{= -12+4(9)}$

$\mathsf{4(9)= \bf 36}$

$\mathsf{-12 + 36 = \bf 24}$

$\boxed{\boxed{\large\text{Answer: \huge\bf Option C. 24}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

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