The length of the midsegment of an isosceles trapezoid is the sum of the two bases, divided by 2. So this means -
(base 1+base2) / 2
(12+20) / 2
32/2
Length of midsegment = 16
We can write this as
(x - 5)^2 + (y + 3)^2 = r^2
where r = radius
Plugging in the point (2,5) we have
(2-5)^2 + (5+3)^2 = r^2
r^2 = 9 + 64 = 73
so the required equation is
(x - 5)^2 + (y + 3)^2 = 73
Answer:
x = 4
Step-by-step explanation:
Given
6x - 5y = 14 ← substitute y = 2 into the equation
6x - 5(2) = 14
6x - 10 = 14 ( add 10 to both sides )
6x = 24 ( divide both sides by 6 )
x = 4
