Step-by-step explanation:

In this type of math equation, you have to multiply all members from the first part with the second part.
Expanded:

simplified:

Answer:
80 < 93 < 121 < 127
Step-by-step explanation:
For a geometric series,

Formula to be used,
Sum of t terms of a geometric series = 
Here t = number of terms
a = first term
r = common ratio
1). 
First term of this series 'a' = 3
Common ratio 'r' = 2
Number of terms 't' = 5
Therefore, sum of 5 terms of the series = 
= 93
2). 
First term 'a' = 1
Common ratio 'r' = 2
Number of terms 't' = 7
Sum of 7 terms of this series = 
= 127
3). 
First term 'a' = 1
Common ratio 'r' = 3
Number of terms 't' = 5
Therefore, sum of 5 terms = 
= 121
4). 
First term 'a' = 2
Common ratio 'r' = 3
Number of terms 't' = 4
Therefore, sum of 4 terms of the series = 
= 80
80 < 93 < 121 < 127 will be the answer.
Answer:
-13/20
Step-by-step explanation:
-4/5 x 4/4 = -16/20
3/20 x 1/1 = 3/20
-16/20 + 3/20 = (-16 + 3 = -13)
-13/20
Speed = 90km/hr
Time = 1min = 1/60 hr
Speed = Distance / Time
Distance = Speed * Time
D = (90 km/hr) * (1/60 hr)
D = 1.5 km (ANSWER)
Answer:
47.74
Step-by-step explanation:
(tax is 8.5% of 100%, so you turn it into a fraction)
44 x .085 = 3.74
44 + 3.74 = 47.74