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Alexandra [31]
3 years ago
8

15% off the original price of $350, plus 6% sales tax

Mathematics
1 answer:
jonny [76]3 years ago
7 0
Step 1. 100-15=85
Step 2. $350 *.85=$297.50
Step 3. $297.50 * .06= $17.85
Step 4. $297.50+17.85=$315.35

Answer: $315.35
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Hyperbola is the answer
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I remember being taught this but I can't remember how to solve it. Can you explain how to get the answer??
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Answer:

342.5 miles or D

Step-by-step explanation:

55 x 3.5 = 192.5

60 x 2.5 = 150

192.5 + 150 = 342.5

This should be it! Please mark me Brainliest :)

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The publisher of a recently released nonfiction book expects that over the first 20 months after its release, the monthly profit
wolverine [178]

Answer:

(a)\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

(b)P'(5)=-($4.54) Thousand

(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

P(t)=\frac{240t-40t^2}{t^2+20}

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

P(t)=\frac{240t-40t^2}{t^2+20} using quotient rule.

\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}

Simplifying

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}

=-($2.10) Thousand of dollars

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6 0
3 years ago
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Step-by-step explanation:

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3 years ago
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The sum of three numbers is 91. the third number is 2 times the first. the first number is 7 less than the second. what are the
PolarNik [594]
Let's call the three numbers a, b, and c.
Now we can turn the information we are given into equations.
The sum of the three numbers is 26:
a + b + c = 26
Twice the first (2 times a) minus the second (2 times a minus b) is 2 less than the third:
2a - b = c - 2
The third is the second minus three times the first:
c = b - 3a
Counting what we have here, we now have three equations and three variables: enough to solve the whole system of equations.
The third equation gives us c directly, so we can start there and substitute into the second equation:
2a - b = (b - 3a) - 2
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Now we have c in terms of a and b, and b in terms of just a. So let's use the first equation and substitute to find out what a is:
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a = 8
At last, we have solved for one of the variables. Now, plug this into the equation for b to find b:
b = (5a + 2) / 2 = (5(8) + 2) / 2 = (40 + 2) / 2 = 42 / 2 = 21
Now we have a and b. Time to find c!
a + b + c = 26
(8) + (21) + c = 26
29 + c = 26
c = 26 - 29
c = -3
<span>So our values for a, b, and c are 8, 21, and -3.</span>
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