Answer:
For 25, the answer is C
Step-by-step explanation:
How I got the answer for 25 is:
To find the mean absolute deviation of the data, start by finding the mean of the data set.
How you do this is first you need to find the sum of the data values, (add all the numbers together) and divide the sum by the number of data values.(and divide that number by how many numbers you added together in the first place)
In this case, we'd be adding 44 + 39 + 47 + 38 + 38 + 41 + 40, and that equals 287. Now we'll divide 287 by how many numbers we added together, which is 7 numbers. 287 ÷ 7 = 41. That's the mean of the data set.
Next, we'll find the absolute deviation of the mean. How we do this is, we find how far away all the numbers are from 41.
44 is 3 away from 41
39 is 2 away from 41
47 is 6 away from 41
38 is 3 away from 41
41 is 0 away from 41
40 is 1 away from 41
So now, we add all of the distances together (3, 2, 6, 3, 0, and 1), and that equals 15! Now we do 15 ÷ 6, which is 2.5 and the reason we're dividing by 6 is because we're dividing by the number of distances we added together. Now, if you look on your worksheet, the closest answer to 2.5 is C, (2.6) so I'd chose that as the correct answer. I hope that helped!
Answer:
The required answer is 
.
Step-by-step explanation:
Consider the provided numbers:
We need to subtract in base 4.
The place value of 201 is:
1 is at units place, 0 is at four's place and 2 is at 4 squared place.
The place value of 32 is:
2 is at units place and 3 is at four's place.
201
- 32
Start subtracting the numbers from the unit place.
Here, we need to subtract 2 from 1, which is not possible so borrow 4 from the four's place but there is 0 at four's place so borrow from 4 squared place and change 2 to 1.
Also change 0 to 4 because we have borrow 4 from squared place.
Now 1 can borrow 4 from the four's place which will become 1+4=5 and change 4 at four's place to 3.
Now the number will look like this:
135
- 32
Now subtract the number as shown.
135
<u>- 32</u>
103
Hence, the required answer is .
Standard Normal Distribution. As discussed in the introductory section, normal distributions do not necessarily have the same means and standard deviations. A normal distribution with a mean of 0 and a standard deviation of 1 is called a standard normal distribution.
