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Harlamova29_29 [7]
3 years ago
15

Need help asap please​

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

a= -17/5 or -3.4

Step-by-step explanation:

Move all terms that don't contain  a  to the right side and solve.

Veronika [31]3 years ago
5 0

Answer:

-3.4

Step-by-step explanation:

-26=10A+8

-26-8=10A

-34=10A

-34/10=A

-3.4=A

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In ΔRST, m < R = 104°, r = 20, and t = 10. Find the m < S, to nearest degree.
Mrrafil [7]

9514 1404 393

Answer:

  47°

Step-by-step explanation:

The law of sines helps you find angle T. From there, you can find angle S.

  sin(T)/t = sin(R)/r

  sin(T) = (t/r)sin(R) = (10/20)sin(104°)

  T = arcsin(sin(104°)/2) ≈ 29°

Then angle S is ...

  S = 180° -R -T = 180° -104° -29°

  ∠S = 47°

5 0
3 years ago
What is the Domain and Range of the function f(x)<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx-7%7D%20%2B9" id="TexFormula1" tit
omeli [17]

For the given function, the domain is D : { x ≥ 7} and the range is R: { y ≥ 9}

<h3>How to get the domain and range?</h3>

Here we have a square root, remember that the argument of the square root must be equal or larger than zero, so the domain is such that:

x - 7 ≥ 0.

Solving for x we get:

x ≥ 0 + 7

Then the domain is:

x ≥ 7

To get the range, we evaluate in the minimum of the domain:

f(7) = √(7 - 7) + 9 = 9

Then the range is the set of all values larger than 9, because the function is increasing.

So the range is R: y ≥ 9.

If you want to learn more about domain and range:

brainly.com/question/10197594

#SPJ1

5 0
2 years ago
Find the coordinates of the vertices of the figure formed by each system of inequalities. x + y &lt; 9 x - 2y &lt; 12 y &lt; 2x
Vladimir [108]

Answer:

b. (10, -1), (-6, -9), (2, 7)

Step-by-step explanation:

One way to solve this problem is by graphing (see attachment). In fact, that actually is the easiest way to do this.

First, graph x + y < 9 (red part on the attachment). To do this, isolate the y so that it's like a regular linear equation: y < -x + 9. Graph the line y = -x + 9 first, and then choose a point either on the left or right of the line to plug in for x and y.

Let's just choose (0, 0), which is on the left of the line: 0 < -0 + 9  ⇒  0 < 9. Since this is a true statement, we know that we should shade the left side of the equation, and not the right side.

Now, graph x - 2y < 12 (blue part on the attachment). It's the same process here as the first inequality. For this one, we find that we also shade to the "left" of the line (it's more "up" than "left", but you get the idea).

Finally, graph y < 2x + 3 (green part on the attachment). Again, it's the same process. For this, we shade to the right.

Now look at the three points that they intersect at: they are (2, 7), (-6, -9), and (10, -1). The answer is thus B.

7 0
3 years ago
Read 2 more answers
Given the following definition, compute Q(5). Q(n) = 0 if n = 0 2 if n = 1 4 if n = 2 Q(n − 1) + Q(n − 2) + Q(n − 3) if n &gt; 2
aalyn [17]
We have 
Q(0)=0\\&#10;Q(1)=2\\&#10;Q(2)=4
and Q(n)=Q(n-1)+Q(n-2)+Q(n-3)\mbox{ when } n\ \textgreater \ 2.
So 
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3 0
3 years ago
How many ways can 10 runners finish first, second, and third in a race?
olga nikolaevna [1]
Let's call the 10 runners A B C D E F G H I J
ABC
ABD
ABE
ABF
ABG
ABH
ABI
ABJ
ACB
ACD
ACE
ACF
ACG
ACH
ACI
ACJ
ADB
ADC
ADE
ADF
ADG
ADH
ADI
ADJ
AEB
AEC
AED
AEF
AEG
AEH
AEI
AEJ
AFB
AFC
AFD
AFE
AFG
AFH
AFI
AFJ
AGB
AGC
AGD
AGE
AGF
AGH
AGI
AGJ
AHB
AHC
AHD
AHE
AHF
AHG
AHI
AHJ
AIB
AIC
AID
AIE
AIF
AIG
AIH
AIJ
AJB
AJC
AJD
AJE
AJF
AJG
AJH
AJI
The above is 60 different ways, but now B C D E F G H I J have to come first, and the proses starts again, until we have covered them all. I'm not going to write them all out but in theory, there is 540 different ways. 9*60=540.
4 0
3 years ago
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