Read below-
Step-by-step explanation:
Expanded forms can be written like a sentence or stacked for readability as they are here.
Expanded Notation Form:
2,000
+ 600
+ 20
+ 5
Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer: 7
Step-by-step explanation:
Use PEMDAS method to solve.
- Parentheses
- Exponents
- Multiplication and Division
- Addition and subtraction.
This means to solve all the numbers in order.
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1 + 2 × 3
=1 + 6 ⇔ First do multiplication
=7 ⇔ Then do division
Step-by-step explanation:
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Answer:
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Step-by-step explanation: