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Degger [83]
3 years ago
7

Please help i will give you brainiest and 5 stars answer the question!!!!!!!!!!!!!!!!!!!!!!!!!

Computers and Technology
1 answer:
QveST [7]3 years ago
5 0

Answer:

He forgot to give credit to the sources at the end.

If you take something from a different source and you quote it, you must give credit at the end or it can go down as plagiarism.

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Please choose the correct citation for the case which established the "minimum contacts" test for a court’s jurisdiction in a ca
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WRITE A JAVA PROGRAM TO PRINT THE PATTERN<br> 13579<br> 2468<br> 357<br> 46<br> 5
Inessa05 [86]

Answer:

import java.util.Scanner;

import java.lang.*;

class Main

{

  public static void main(String args[])

  {

     int n;

     //For capturing the value of n

     Scanner scanner = new Scanner(System.in);

     System.out.println("Enter the value of n:");

     //The entered value is stored in the var n

     n = scanner.nextInt();

     int k=1;

     printnum(n,k);  

  }

  public static void printnum(int n,int k)

  {

       if(n%2==0)

       {

       for(int i=k;i<=n-1;i=i+2)

            {

                System.out.print(i);

            }    

        System.out.println("");

       }

       else

        {

       for(int i=k;i<=n-1;i=i+2)

            {

                System.out.print(i);

            }    

        System.out.println("");

        }

      n--;

      if(n<=1)

      {

         System.exit(0);

      }

      else

      {

          printnum(n,k+1);

      }

   }

}

Explanation:

The program is self explanatory.

4 0
3 years ago
Create a program in c/c++ which accepts user input of a decimal number in the range of 1 -100. Each binary bit of this number wi
kirill115 [55]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

void switch_fun(int input)

{

//array to store binary of input number

   int bin[7];

   // convert the number into binary

   for(int i=0; input>0; i++)

       {

           bin[i]=input%2;

           input= input/2;

       }

   // print the switch number and their status

   cout<<"Switch number:\t 1\t 2\t 3\t 4\t 5\t 6\t 7 \n";

   cout<<"status:      ";

   for(int j=6;j>=0;j--)

   {

   // if bit is 1 print "ON" else print "OFF"

       if(bin[j]==1)

           cout<<"\t ON";

       else

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   }

}

int main()

{

   int n;

   cout<<"enter the number between 1-100 only:");

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   cin>>n

   // validate the input

   while(n<1 ||n>100)

   {

     cout<<"wrong input!! Input must be in between 1-100:"<<endl;

     cout<<"enter the number again :";

     cin>>n;

   }

// call the function with input parameter

  switch_fun(n);

return 0;

}

Explanation:

Read a decimal number from user. If the number is not between 1 to 100 the it will again ask user to enter the number until the input is in between 1-100.Then it will call the fun() with parameter n. First it will convert the decimal to binary array of size 7.Then print the status of switch.If bit is 1 then print "ON" else it will print "OFF".

Output:

enter the number between 1-100 only:-5

wrong input!! Input must be in between 1-100:

enter the number again :125

wrong input!! Input must be in between 1-100:

enter the number again :45

Switch number:   1       2       3       4       5       6       7

Status:          OFF     ON      OFF     ON      ON      OFF     ON

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