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3 years ago

Math help please I need it ASAP

Mathematics

1 answer:

statuscvo [17]3 years ago

4 0

Answer:

x=10.5

Step-by-step explanation:

$\frac{x}{6} =\frac{7}{4} \\x=\frac{7}{4} \times 6\\=\frac{21}{2} \\=10.5$

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Mariko and Kell are working jobs that they get paid by the hour.

marin [14]

Answer:

Kell makes $8.50 an hour

Kell makes $1.50 more an hour

Add all three money earned by the total hours worked. 8.50

Step-by-step explanation:

4 0

3 years ago

How do you work out pie charts if thewy don't have any numbers on them?

abruzzese [7]

Adding on to the previous, estimate FRACTIONS of the chart, and then figure out the percentage of those fractions

6 0

4 years ago

Which equation is the equation of a line that is perpendicular to x + 2y = 16?

AnnyKZ [126]

Answer:

$y=2x-2$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x=0)

Perpendicular lines always have slopes that are negative reciprocals. For example, 2 and -1/2. 3/4 and -4/3.

To determine whether a line is perpendicular to $x + 2y = 16$ , we must first determine its slope. Rearrange the given equation into slope-intercept form:

$x + 2y = 16\\\\2y =-x+ 16\\\\y=\displaystyle -\frac{1}{2}x +\frac{16}{2} \\\\y=\displaystyle -\frac{1}{2}x +8$

From this, we can clearly tell that the slope (m) of the line is $\displaystyle -\frac{1}{2}$ .

The negative reciprocal of $\displaystyle -\frac{1}{2}$ is 2. Therefore, the slope of a perpendicular line would be 2.

Therefore, the correct answer option would be $y=2x-2$ .

I hope this helps!

8 0

3 years ago

What is the slope of a line perpendicular to the line whose equation is x-y=5x−y=5.

stepladder [879]

Answer:

Step-by-step explanation:

5 0

3 years ago

Charles begins finding the volume of a trapezoidal prism using the formula A = One-half(b1 + b2)h to find the prism's base area.

yKpoI14uk [10]

Answer:

The expression that can be used to represent the volume of the trapezoidal prism is $(2x^3+6x^2)$

Step-by-step explanation:

step 1

Find the area of the trapezoidal base

The area of a trapezoid is given by the formula

$A=\frac{1}{2}(b_1+b_2)h$

we have

$b_1=(x+2)\ units\\b_2=(x+4)\\h=x$

substitute

$A=\frac{1}{2}(x+2+x+4)x$

$A=\frac{1}{2}(2x+6)x$

$A=(x+3)x\\A=(x^2+3x)\ units^2$

step 2

Find the volume of the trapezoidal prism

we know that

The volume of the prim is given by

$V=Bh$

where

B is the area of the base

H is the height of the prism

we have

$B=(x^2+3x)\ units^2$

$H=2x\ units$

substitute

$V=(x^2+3x)2x\\V=(2x^3+6x^2)\ units^3$

therefore

The expression that can be used to represent the volume of the trapezoidal prism is

$(2x^3+6x^2)$

7 0

3 years ago

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