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Digiron [165]
3 years ago
11

Math help please I need it ASAP

Mathematics
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

x=10.5

Step-by-step explanation:

\frac{x}{6} =\frac{7}{4} \\x=\frac{7}{4} \times 6\\=\frac{21}{2} \\=10.5

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Jared painted 5/12 and 4/12 blue.what part of the mug is not red or blue?
Reika [66]
3/12 of the mug is not blue or red
7 0
3 years ago
Not sure how difficult this would be to solve
mr_godi [17]
F (x) = x^2 - 2x + 1
f (x) = (-2)^2 - 2(-2) + 1
= 4 + 4 + 1
= 9
f (x) = ( 0 )^2 - 2 (0) + 1
= 0 - 0 + 1
= 1
0 = x^2 - 2x + 1
x^2 = 2x - 1 = 1
f (2) = 2^2 - 2(2) + 1
= 4 - 4 + 1
= 1
f (3) = 3^2 - 2(3) + 1
= 9 - 6 + 1
= 3 + 1
= 4

3 0
2 years ago
13 less than 8 times a number is the same as the number plus 1
aliya0001 [1]
8x - 13 = x + 1
Solve for x
Add 13
8x = x + 14
Subtract x
7x = 14, x = 2
Answer: the number is 2
7 0
3 years ago
Suzy has an Etsy store where she sells shirts. Her shirts come in five sizes: small, medium, large, extra-large, or 2XL. Her shi
Shalnov [3]

Answer:

25

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Which function has an asymptote at x= 39
LekaFEV [45]

Answer:

option B : f(x)= log_7(x-39)

Step-by-step explanation:

(a) f(x) = 7^{x-39}

For exponential function , there is no vertical asymptotes

General form of exponential function is

f(x) = n^{ax-b}+k

f(x) = 7^{x-39}

In the given f(x) the value of k =0

So horizontal asymptote is y=0

(b) lets check with option

f(x)= log_7(x-39)

To find vertical asymptote we set the argument of log =0  and solve for x

Argument of log is x-39

x-39=0 so x=39

Hence vertical asymptote at x=39


3 0
4 years ago
Read 2 more answers
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