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Digiron [165]
2 years ago
11

Math help please I need it ASAP

Mathematics
1 answer:
statuscvo [17]2 years ago
4 0

Answer:

x=10.5

Step-by-step explanation:

\frac{x}{6} =\frac{7}{4} \\x=\frac{7}{4} \times 6\\=\frac{21}{2} \\=10.5

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The answer is -143231 
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Read 2 more answers
Please help me with this one I don’t understand. I need help with #20 thank you!
dimaraw [331]

part A)

we know that for every 1000 ft the temperature drops by 1.3.

so after 1000ft up it went down by 1.3(1)

2000ft up it went down by 1.3(2) or 2.6

3000ft up it went down by 1.3(3) or 3.9

after 10000 up it went down by 1.3(10) or 13.

part B)

well, the current temperature on the ground where the plane is sitting is -2.8°F, after 10000ft it dropped by 13°, so the temperature will just be -2.8 - 13 = -15.8°F.

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3 years ago
Z divided by 3-2z + 4(z-8) when z = 18 <br><br> A. -122<br> B. 6<br> C. -66<br> D. 10
murzikaleks [220]

Everywhere you see z, replace the letter with 18.

z/[(3- 2z)] + 4(z - 8)

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You finish.

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Step-by-step explanation:

6 0
2 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
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