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Yanka [14]
2 years ago
13

The equation of a circle is (x - 4)2 + (y - 4)2 = 9. The point (4, 1) is on the circle.

Mathematics
1 answer:
Alika [10]2 years ago
3 0

Answer:

4

Step-by-step explanation:

the answer is 4 hope it helps

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6+n/5=9<br><br> What is happening to the variable? <br><br><br> How do you solve for the variable?
Svetradugi [14.3K]

Answer:

n=15

Step-by-step explanation:

(subtract 6 from both sides of the equation.)

6+n/5=9

6+n/5-6=9-6

(Now you will have to simplify.)

n/5=3

(You will have to multiply all terms by the same value to eliminate fraction denominators.)

n/5=3

5xn/5=5x3

(You will now have to simplify.)

n=15

And that's how you get your answer.

i hope this helps.      :)

7 0
3 years ago
This is really easy! pic below..
KATRIN_1 [288]
The answer is A.
I think so because each one of them agrees with 20x and 15
5 0
3 years ago
Help me please with this math. find x and y​
erastova [34]

Answer:X= 1.84. Y= 3.08

Step-by-step explanation:

-9x+8y =8 ............i

-8x+10y= -16........ii

Multiply equation I by 8

Multiply equation ii by 9

-72x+64y = 64 ..... iii

-72x+90y = 144 ..... iv

Subtract iv from iii

-26y = -80

y= 80/26

y= 3.08

Put the value of y in equation i

-9x+8y =8

-9x+8(3.08) = 8

-9x+24.64 = 8

-9x = 8-24.64

-9x=-16.64

Divide both side by 9

-9x/-9 = -16.64/-9

X= 1.84

3 0
3 years ago
Almee is decorating her new house. she found a table at pier one for $425. If the table is 25% off, what will it cost
serious [3.7K]

Answer:

$318.75

Step-by-step explanation:

425*0.25=106.25         425-106.25=318.75

6 0
3 years ago
Read 2 more answers
The reactants of two reactions are shown.
katovenus [111]

Answer:

The answer to your question is letter B.

Step-by-step explanation:

The correct answer is letter B because both Copper and Iron as reactants have an oxidation number of zero and when they have reacted their oxidation numbers would be different from those.

A redox reaction is a reaction that involves a transfer of electrons from one atom to another and the oxidation numbers of the reactants are different from the oxidation numbers from the products.

4 0
3 years ago
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