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2 years ago

Formula unit of Magnesium oxide and Calcium bicarbonate and aluminum carbonate plzzzz

Chemistry

1 answer:

Fudgin [204]2 years ago

5 0

Magnesium oxide : MgO

Calcium bicarbonate: Ca(HCO3)2

aluminum carbonate: Al2(CO3)3 or C3Al2O9

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What alkene(s) would be produced from the dehydration of cyclopentanol?

Ronch [10]

The dehydration of cyclopentanol is shown in the balanced equation below:

Cyclopentanol => cyclopentene + H2O

Therefore, the alkene produced from the dehydration of cyclopentanol is cyclopentene.

The OH group is removed from the compound resulting to an alkene, cyclopentene. <span />

7 0

3 years ago

How many molecules are there in 42 grams of AIF3

Sever21 [200]

Answer:

The correct answer is - 3.012×10^23 molecules

Explanation:

The number of molecules is present in any mole of an element or compound are the same. To find the molecules you need to multiply the number of the moles of the compound by Avogadro's number:

Moles are calculated from the molecular weight, for AlF3

= 26.98 + 3×19

= 26.98 + 57

= 83.98

Then moles in 42 grams:

= 42/83.98

= 0.5001190 moles

Now the number of molecules = moles*Avogadro's number

= 0.500110×6.022×10^23

= 3.011×10^23 molecules

7 0

3 years ago

Which compound would most likely turn litmus paper to a red color?

sleet_krkn [62]

Answer D, because it's acid

3 0

3 years ago

Dissolving 5.28 g of an impure sample of calcium carbonate in hydrochloric acid produced 1.14 L of carbon dioxide at 20.0 °C and

swat32

Answer:

$\%\ mass\ of\ CaCO_3=93.37\ \%$

Explanation:

Given that:

Pressure = 791 mmHg

Temperature = 20.0°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (20 + 273.15) K = 293.15 K

T = 293.15 K

Volume = 100 L

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 62.3637 L.mmHg/K.mol

Applying the equation as:

791 mmHg × 1.14 L = n × 62.3637 L.mmHg/K.mol × 293.15 K

⇒n of $CO_2$ produced = 0.0493 moles

According to the reaction:-

$CaCO_3 + 2 HCl\rightarrow CaCl_2 + H_2O + CO_2$

1 mole of carbon dioxide is produced 1 mole of calcium carbonate reacts

0.0493 mole of carbon dioxide is produced 0.0493 mole of calcium carbonate reacts

Moles of calcium carbonate reacted = 0.0493 moles

Molar mass of $CaCO_3$ = 100.0869 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.0493\ mol= \frac{Mass}{100.0869\ g/mol}$

$Mass_{CaCO_3}=4.93\ g$

Impure sample mass = 5.28 g

Percent mass is percentage by the mass of the compound present in the sample.

$\%\ mass\ of\ CaCO_3=\frac{Mass_{CaCO_3}}{Total\ mass}\times 100$

$\%\ mass\ of\ CaCO_3=\frac{4.93}{5.28}\times 100$

$\%\ mass\ of\ CaCO_3=93.37\ \%$

3 0

2 years ago

The process that fuels a star is BEST described as________.

erik [133]

Hydrogen fusion is the answer. It is also known as <span>hydrogen burning. </span>

6 0

2 years ago

Formula unit of Magnesium oxide and Calcium bicarbonate and aluminum carbonate plzzzz​

Formula unit of Magnesium oxide and Calcium bicarbonate and aluminum carbonate plzzzz