The best method to solve how many grams of sodium nitrate that will be dissolve in water at 20 degrees Celsius is to use solubility table. Based on the solubility table, 88.3 g will dissolve in water in a 100g NaNO3. Therefore, get the percentage and multiply it to 50g. The answer is 44.15g
Answer:
Peptide bonds form from nucleophilic attack by an α‑carboxyl carbon atom on an electron pair of an α‑amino nitrogen atom of another amino acid.
Explanation:
Peptide bond is a form of covalent bond and it is Amide type that is formed between two molecules when carboxyl group react with one molecule of amino group to release molecule of water.The peptide bond are in form pseudo-double bond characteristic; rigid, planar, and stronger than a typical Carboxyl nitrogen single bond.
Peptide bonds form from nucleophilic attack by an α‑carboxyl carbon atom on an electron pair of an α‑amino nitrogen atom of another amino acid.
Answer:
4
Explanation:
It should be 4
The mass is 9
There are 5 neutrons
There are 9 - 5 = 4 protons
So it is the 4th element on the periodic table.
Answer: a. BaO
Explanation:
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Here element barium is having an oxidation state of +2 called as 
cation and 
is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral 
Na2CO3 mol = mass/rfm
= 91.9 / ( 23+23+12+16+16+16)
= 91.9/106
=919/1060 or roughly 0.867
Mole ratio of sodium carbonate to calcium carbonate is 1:1
Therefore calcium carbonate mol = mass/rfm
919/1060 = mass / (40+12+16+16+16)
919/1060 = mass / 100
Mass = 919/1060 x 100
= 4595/53 or 86.7g to 3 significant figures
