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Advocard [28]
2 years ago
5

Using g= 10 m/s?, find the weight of a 3 kg mass.

Chemistry
1 answer:
Wewaii [24]2 years ago
3 0

Answer:

30 N

Explanation:

weight = mass * g

w = mg

w 3*10

w = 30

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If the temperature of a gas doubles and the volume stays the same, what will happen to the pressure?
dangina [55]

Answer:

The value of pressure must be increased double times.

Explanation:

pV = nRT ( the Ideal Gas Law ) =>

p = nRT / V

So, when T is doubled, we write 2T to the formula:

p(new pressure) = nR x 2T / V = 2 x p(original)

=> If the temperature of a gas doubles and the volume stays the same, the value of pressure must be increased double times.

I hope this answer can help you. Have a nice day!

6 0
3 years ago
How do weathering and deposition differ? (4 points)
kiruha [24]

Answer:

Oa. Weathering breaks down rocks; deposition leaves them in new places.

Explanation:

Did test and got it right.

6 0
3 years ago
During an experiment,what is the factor you are testing called
Step2247 [10]

Answer:

the answer is variable

4 0
3 years ago
The respiratory system is what brings in food and breaks it down True or false
Gala2k [10]

Answer:

false

Explanation:

the respiratory system includes the lungs and heart

not food

5 0
3 years ago
Use the periodic table to identify the element with the electron configuration 1s²2s²2p⁴. Write its orbital diagram, and give th
natta225 [31]

Answer:

1. Orbital diagram

2p⁴   ║ ↑↓ ║  "↑"  ║   ↑

2s²    ║ ↑↓ ║

1s²     ║ ↑↓ ║

2. Quantum numbers

  • <em>n </em>= 2,
  • <em>l</em> = 1,
  • m_{l} = 0,
  • m_{s} = +1/2

Explanation:

The fill in rule is:

  • Follow shell number: from the inner most shell to the outer most shell, our case from shell 1 to 2
  • Follow the The Aufbau principle, 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p
  • Hunds' rule: Every orbital in a sublevel is singly occupied before any orbital is doubly occupied. All of the electrons in singly occupied orbitals have the same spin (to maximize total spin).

So, the orbital diagram of given element is as below and the sixth electron is marked between " "

2p⁴   ║ ↑↓ ║  "↑"  ║   ↑

2s²    ║ ↑↓ ║

1s²     ║ ↑↓ ║

The quantum number of an electron consists of four number:

  • <em>n </em>(shell number, - 1, 2, 3...)
  • <em>l</em> (subshell number or  orbital number, 0 - orbital <em>s</em>, 1 - orbital <em>p</em>, 2 - orbital <em>d...</em>)
  • m_{l} (orbital energy, or "which box the electron is in"). For example, orbital <em>p </em>(<em>l</em> = 1) has 3 "boxes", it was number from -1, 0, 1. Orbital <em>d</em> (<em>l </em>= 2) has 5 "boxes", numbered -2, -1, 0, 1, 2
  • m_{s} (spin of electron), either -1/2 or +1/2

In our case, the electron marked with " " has quantum number

  • <em>n </em>= 2, shell number 2,
  • <em>l</em> = 1, subshell or orbital <em>p,</em>
  • m_{l} = 0, 2nd "box" in the range -1, 0, 1
  • m_{s} = +1/2, single electron always has +1/2
3 0
4 years ago
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