Answer:
![y^{10}](https://tex.z-dn.net/?f=y%5E%7B10%7D)
Step-by-step explanation:
I am assuming that you mean
.
![y^4*y^6\\\text {Apply the product rule: } a^n*a^m =a^{n+m}\\4 + 6 = 10\\\text {Therefore,}\\\boxed {y^4*y^6 = y^{10}}](https://tex.z-dn.net/?f=y%5E4%2Ay%5E6%5C%5C%5Ctext%20%7BApply%20the%20product%20rule%3A%20%7D%20a%5En%2Aa%5Em%20%3Da%5E%7Bn%2Bm%7D%5C%5C4%20%2B%206%20%3D%2010%5C%5C%5Ctext%20%7BTherefore%2C%7D%5C%5C%5Cboxed%20%7By%5E4%2Ay%5E6%20%3D%20y%5E%7B10%7D%7D)
<em>Brainilest Appreciated.</em>
<em><u>Question:</u></em>
Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.
The complete figure of this question is attached below
<em><u>Answer:</u></em>
<h3>The perimeter of the quadrilateral is 129 inches</h3>
<em><u>Solution:</u></em>
The complete figure of this question is attached below
Given that, a quadrilateral with,
Side lengths are:
![4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches](https://tex.z-dn.net/?f=4x%5E2%20%2B%208x%5C%20inches%20%5C%5C%5C%5C3x%5E2-5x%2B20%5C%20inches%20%5C%5C%5C%5C7x%20%2B%2030%5C%20inches%20%5C%5C%5C%5C31%5C%20inches)
The values of the side lengths when x = 2 are
![(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch](https://tex.z-dn.net/?f=%284x%5E2%2B8x%29%3D%284%5Ctimes%202%5E2%2B8%5Ctimes%202%29%3D%284%5Ctimes%204%2B16%29%3D16%2B16%3D32%5C%20inch%5C%5C%5C%5C%283x%5E2-5x%2B20%29%3D%283%5Ctimes%202%5E2-5%5Ctimes%202%2B20%29%3D%283%5Ctimes%204-10%2B20%29%3D12%2B10%3D22%5C%20inch%5C%5C%5C%5C%287x%2B30%29%3D%287%5Ctimes%202%2B30%29%3D14%2B30%3D44%5C%20inch)
Perimeter of a quadrilateral = Sum of its sides
Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches
Thus perimeter of the quadrilateral is 129 inches
Answer:
-17
Step-by-step explanation:
-6-11=-17
Part A is basically asking you for the GCF (greatest common factor) between 63 and 36. To find this you find all the numbers that can be multiplied to form each number.
36:
1 * 36
2*18
3*12
4*9
6*6
63:
1*63
3*21
9*7
The GCF is 9.
Part B is asking how much the GCF can go into each type of flower.
4 rows of geraniums
7 rows of marigolds
The initial term of this geometric series is 4, and the common ratio is -1/2. The sum is given by
![S_{n}=a_{1}\dfrac{r^{n}-1}{r-1}\\\\S_{10}=4\cdot \dfrac{(-\frac{1}{2})^{10}-1}{-\frac{1}{2}-1}=4\cdot \dfrac{(\frac{1}{1024}-1)}{(-\frac{3}{2})}\\\\=\dfrac{8}{3}\cdot \dfrac{1023}{1024}=\dfrac{341}{128}](https://tex.z-dn.net/?f=S_%7Bn%7D%3Da_%7B1%7D%5Cdfrac%7Br%5E%7Bn%7D-1%7D%7Br-1%7D%5C%5C%5C%5CS_%7B10%7D%3D4%5Ccdot%20%5Cdfrac%7B%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B10%7D-1%7D%7B-%5Cfrac%7B1%7D%7B2%7D-1%7D%3D4%5Ccdot%20%5Cdfrac%7B%28%5Cfrac%7B1%7D%7B1024%7D-1%29%7D%7B%28-%5Cfrac%7B3%7D%7B2%7D%29%7D%5C%5C%5C%5C%3D%5Cdfrac%7B8%7D%7B3%7D%5Ccdot%20%5Cdfrac%7B1023%7D%7B1024%7D%3D%5Cdfrac%7B341%7D%7B128%7D)
The sum is
approximately 2.66.