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2 years ago

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Mathematics

2 answers:

Bezzdna [24]2 years ago

5 0

Answer:

Step-by-step explanation:

alekssr [168]2 years ago

4 0

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So Ace has 50 chocolate bars and wants to split with his 12 friend equaly

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

You can divide 50 ÷ 12, which will have remainding chocolate bars.

50 ÷ 12 = 4.1666666667

Each person will get 4 bars.

Since there's numbers before the decimal, there is remaining chocolachocolate bars that won't be shared.

4 × 12 = 48

There is a remaining amount of candy bars (2).

So, each of the 12 friends will get 4 bars, as 2 will be left over.

Hope this helped !

6 0

1 year ago

Read 2 more answers

Help....................btw school test

alina1380 [7]

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7 0

3 years ago

Read 2 more answers

60 ft/s = ____km/h I don't know how to convert feet to kilometers.

kondor19780726 [428]

Well to convert feet into km you have to know that 1 feet = 0.0003048 km

knowing that you multiply the km by 60 which gives you..... 0.018288 km

7 0

2 years ago

PLEASE HELP

melisa1 [442]

Step-by-step explanation:

4 0

2 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

$P(X >300 ) = 0.97219$

8 0

2 years ago