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2 years ago

5 times 5 grggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggrfgrrrrrrrrrrrrrrrrrrrrrrr

Mathematics

2 answers:

Bezzdna [24]2 years ago

5 0

Answer:

Step-by-step explanation:

alekssr [168]2 years ago

4 0

25 gggggggggggggggggggggggg

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Can someone help me with this?

jekas [21]

Answer:

$\huge\purple{ x^2 +(y+2)^2 = 4}$

Step-by-step explanation:

Circle is centred at (0, -2)

-> h = 0 & k = - 2

radius of the circle (r) = y-coordinate of the center = - 2

Equation of circle in standard form is given as:

$(x-h)^2 +(y-k)^2 = r^2$

Plugging the values of h, k and r in the above equation, we find:

$(x-0)^2 +[y-(-2)]^2 = (-2)^2$

$\implies\huge\orange{ x^2 +(y+2)^2 = 4}$

This is the required equation of circle.

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1 year ago

Which system of linear inequalities is represented by the graph?

MrRa [10]

Im not good in math and this is my first question, my best guess is D

I will investigate tommorow this problem a little bit more... <3

5 0

3 years ago

Read 2 more answers

Can someone plss help mee ??

Dvinal [7]

First - 8
second - 4
third - 12
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3 0

2 years ago

A person borrows $50000 loan from bank at a rate of 10% for 5 years compounded yearly.

Hatshy [7]

<h3>Given:</h3>

P= $50,000
R= 10%
T= 5 years

P= Principal amount
R= Rate of interest
T= Time period

<h3>Solution:</h3>

$\large\boxed{Formula: A= P(1+ \frac{R}{100}{)}^{T}}$

Let's substitute according to the formula.

$A= 50000(1+ \frac{10}{100}{)}^{5}$

A= $80525.5

Now, we can find the interest paid

$\large\boxed{I= A-P}$

We'll have to deduct the total amount from the principal amount.

Let's substitute according to the formula.

$I= 80525.5-50000$

I= $30525.5

Hence, the total amount paid after 5 years is $80525.5 and $30525.5 was paid as interest.

7 0

2 years ago

Use the equation a = IaIâ

german

Answer:

a) $\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }$

b) $\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }$

c) $\:\:=7\cdot \frac{\:\:}{7}$

Step-by-step explanation:

a) Let a=<2,1,-3>

The magnitude of a is $|a|=\sqrt{2^2+1^2+(-3)^2}$

$|a|=\sqrt{4+1+9}=\sqrt{14}$

The unit vector in the direction of a is

$\hat{a}=\frac{\:\:}{\sqrt{14} }$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }$

b) Let a=2i - 3j + 4k

$|a|=\sqrt{2^2+(-3)^2+4^2}$

$|a|=\sqrt{4+9+16}=\sqrt{29}$

$\hat{a}=\frac{\:\:}{\sqrt{29} }$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }$

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

$|a|=\sqrt{3^2+6^2+(-2)^2}$

$|a|=\sqrt{9+36+4}=\sqrt{49}=7$

The unit vector in the direction of a is

$\hat{a}=\frac{\:\:}{7}$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=7\cdot \frac{\:\:}{7}$

5 0

3 years ago