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kap26 [50]
3 years ago
15

On discovering that her family had a 70% risk of heart attack, Erin took a treadmill test to check her own potential of having a

heart attack. The doctors told her that the reliability of the stress test is 67%. The test predicted that Erin will not have a heart attack. What is the probability after the test was taken that she will not have a heart attack?
A.) 0.099
B.) 0.201
C.) 0.231
D.) 0.469
Mathematics
2 answers:
Ghella [55]3 years ago
8 0
The probability of Erin not having a heart attack according to her family history would be 30%.

The probability of the test predicting correctly is 67%.

Therefore, the probability of the test correctly predicting that Erin will not have a heart attack would be (0.30)(0.67) = 0.201 or 20.1%.
BaLLatris [955]3 years ago
3 0

Answer:

I don't know what the answer is, but the test say B. 201 is wrong

Step-by-step explanation:

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The first derivative of x^2+2y^2=16 is -x/(2y), the second is -(2y^2+x^2)/(4y^3). Find the third implicit derivative of x^2+2y^2
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Answer:

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

Step-by-step explanation:

d²y/dx² = (-2y² − x²) / (4y³)

Take the derivative (use quotient rule and chain rule):

d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²

d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)

d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)

d³y/dx³ = ((8y⁴ + 12x²y²) dy/dx − 8xy³) / (16y⁶)

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Substitute:

d³y/dx³ = ((2y² + 3x²) (-x / (2y)) − 2xy) / (4y⁴)

d³y/dx³ = ((2y² + 3x²) (-x) − 4xy²) / (8y⁵)

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

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