T.J. invests $8,100 in an account

Jason's mom drove at 100 km/h for a 160 km trip. How much longer would

choli [55]

Answer:

Here is the way to get the answer

Step-by-step explanation:We use the formule: t=S/v. So:

+ t1= 160/100 = 8/5 hrs = 5760''

+ t2= 160/90 = 16/9 hrs = 6400''

=> t2-t1= 6400 - 5760 = 640'' = 10'40''

4 0

2 years ago

Read 2 more answers

I need help on 9 11 14 and 16

TEA [102]

Answer:

For 9 the answer is (4)

For 11 the answer is (5)

For 14 the answer is (4)

I cant see number 16 so maybe retake the photo thanks!

Step-by-step explanation:

9. squares have two sets of parallel lines

11. The only quadrilateral that has 3 different side lengths on this list is a trapezoid

14. It has no right angles meaning its not a square or rectangle. It has two sets of parallel sides meaning its not a trapezoid, and since it gives two different side lengths its not a rhombus since all sides muse be congruent to be a rhombus. The only one that matches is 4 a parallelogram

7 0

3 years ago

Talia took the bus from her home to the bank and then walked back to her home along the same route. The bus traveled at an avera

Mekhanik [1.2K]

Answer: The bus traveled at an average speed of 40 km/h and she - 2385764. ... bus from her home to the bank and then walked back to her home along the same route. ... To determine the time, x, that it took Talia to walk home, she used the equation 40(0.9 – x) = 5x. 1 ... Therefore, it took Talia 0.8 hour to walk home or 48 minutes

Step-by-step explanation:

6 0

2 years ago

Two teams A and B play a series of games until one team wins three games. We assume that the games are played independently and

Olenka [21]

Answer:

The probability that the series lasts exactly four games is $3p(1-p)(p^{2} + (1 - p)^{2})$

Step-by-step explanation:

For each game, there are only two possible outcomes. Either team A wins, or team A loses. Games are played independently. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

We also need to know a small concept of independent events.

Independent events:

If two events, A and B, are independent, we have that:

$P(A \cap B) = P(A)*P(B)$

What is the probability that the series lasts exactly four games?

This happens if A wins in 4 games of B wins in 4 games.

Probability of A winning in exactly four games:

In the first two games, A must win 2 of them. Also, A must win the fourth game. So, two independent events:

Event A: A wins two of the first three games.

Event B: A wins the fourth game.

P(A):

A wins any game with probability p. 3 games, so n = 3. We have to find P(A) = P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(A) = P(X = 2) = C_{3,2}.p^{2}.(1-p)^{1} = 3p^{2}(1-p)$

P(B):

The probability that A wins any game is p, so P(B) = p.

Probability that A wins in 4:

A and B are independent, so:

$P(A4) = P(A)*P(B) = 3p^{2}(1-p)*p = 3p^{3}(1-p)$

Probability of B winning in exactly four games:

In the first three games, A must win one and B must win 2. The fourth game must be won by 2. So

Event A: A wins one of the first three.

Event B: B wins the fourth game.

P(A)

P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(A) = P(X = 1) = C_{3,1}.p^{1}.(1-p)^{2} = 3p(1-p)^{2}$

P(B)

B wins each game with probability 1 - p, do P(B) = 1 - p.

Probability that B wins in 4:

A and B are independent, so:

$P(B4) = P(A)*P(B) = 3p(1-p)^{2}*(1-p) = 3p(1-p)^{3}$

Probability that the series lasts exactly four games:

$p = P(A4) + P(B4) = 3p^{3}(1-p) + 3p(1-p)^{3} = 3p(1-p)(p^{2} + (1 - p)^{2})$

The probability that the series lasts exactly four games is $3p(1-p)(p^{2} + (1 - p)^{2})$

8 0

3 years ago

Mrs. Hicks has 35 students in her chemistry class. The ratio of girls to boys is 3:4. How many girls does she have in her class?

solmaris [256]

3+4 =7
35/7 = 5
5 * 3 = 15

there are 15 girls

7 0

3 years ago