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Kay [80]
3 years ago
14

T.J. invests $8,100 in an account

Mathematics
1 answer:
QveST [7]3 years ago
6 0

Answer:

I don't know

Step-by-step explanation:

if don't know

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At Martin Luther King Jr. High School 7 out of 9 students voted to plant trees at the front of the school. A total of 119 voted
mafiozo [28]

Answer:

D

Step-by-step explanation:

hi i am NyLa. i am the founder of "BGP" Blckgirlpower. I just opened new spots on my team if you want to join email me at fnyla36 comment to join. You have to be 11- 13 its ok to be shy but at least give it a chance. Hope to see you soon !

4 0
3 years ago
Read 2 more answers
find the common difference and the three terms in the sequence after the last one given -39 -33 -27 -21​
Serggg [28]

Answer:

Common difference:6 3 terms: -15, -9. -3

Step-by-step explanation:

-39, -33, -27, and -21 all have a difference of 6.

6 0
3 years ago
By how many degrees did the direction of the boat change
gulaghasi [49]

Answer:

The boat turned <u>39°</u> degrees when it made its first turn.

Step-by-step explanation:

The question is as following:

A boat traveled north for 28 miles, then tuned x° south west and traveled for 25 miles before stopping. When it stopped, the boat was 18 miles from its starting point.

By how many degrees did the direction of the boat change when it made its first turn? Round to the nearest degree.

===================================================

See the attached figure which represent explanation of the problem.

The boat start from point A to point B then stopped at point C

AB = 28 miles, BC = 25 miles and AC = 18 miles.

It is required to find the angle x

By applying the cosine Rule:

AC² = AB² + BC² - 2 * AB * BC * cos x

18² = 28² + 25² - 2 * 28 * 25 * cos x

2 * 28 * 25 * cos x = 28² + 25² - 18²

1400 cos x = 1085

Cos x = 1085/1400 = 0.775

x = Cos⁻¹ 0.775 = 39.2° = 39° to the nearest degree.

So, the boat turned <u>39°</u> degrees when it made its first turn.

8 0
3 years ago
The figure shows the layout of a symmetrical pool in a water park. What is the area of this pool rounded to the tens place? Use
k0ka [10]

Answer:

2489ft^{2}

Step-by-step explanation:

The pool are is divided into 4 separated shapes: 2 circular sections and 2 isosceles triangles. Basically, to calculate the whole area, we need to find the area of each section. Due to its symmetry, both triangles are equal, and both circular sections are also the same, so it would be enough to calculate 1 circular section and 1 triangle, then multiply it by 2.

<h3>Area of each triangle:</h3>

From the figure, we know that <em>b = 20ft </em>and <em>h = 25ft. </em>So, the area would be:

A_{t}=\frac{b.h}{2}=\frac{(20ft)(25ft)}{2}=250ft^{2}

<h3>Area of each circular section:</h3>

From the figure, we know that \alpha =2.21 radians and the radius is R=30ft. So, the are would be calculated with this formula:

A_{cs}=\frac{\pi R^{2}\alpha}{360\°}

Replacing all values:

A_{cs}=\frac{(3.14)(30ft)^{2}(2.21radians)}{6.28radians}

Remember that 360\°=6.28radians

Therefore, A_{cs}=994.5ft^{2}

Now, the total are of the figure is:

A_{total}=2A_{t}+2A{cs}=2(250ft^{2} )+2(994.5ft^{2})\\A_{total}=500ft^{2} + 1989ft^{2}=2489ft^{2}

Therefore the area of the symmetrical pool is 2489ft^{2}

3 0
3 years ago
A candy company claims that its jelly bean mix contains 15% blue jelly beans. Suppose that the candies are packaged at random in
I am Lyosha [343]

Answer:

Doubtful.

Step-by-step explanation:

Our values are,

P=0.15 \rightarrow 15\%Jelly Bean Mix.

The sample for us is n=200

And our proportion (x) is 40 .

We can calculate  with this dates the sample proportion and make he test statistic.

p=\frac{x}{n} = \frac{40}{200} = 0.20

H_0:P=0.15

H_1:P \neq 0.15

We use the formula for Test statistic, that is given by,

z= \frac{p-P}{\sqrt{\frac{P-(1-P)}{n}}}

z= \frac{0.20-0.15}{\sqrt{\frac{0.15(1-0.15)}{200}}}

z= 1.98

We see that our P-value: 0.048 (From the Table)

We note that p-value is less than 0.05, so we should to rejecyt the null hypothesis and conclude that the calim is doubtful

4 0
3 years ago
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