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IgorLugansk [536]
2 years ago
14

Helppppp which one is it?

Mathematics
1 answer:
nordsb [41]2 years ago
8 0
C because of the step by step explanation an i’m sorry
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Due in 15 please help!!!
Deffense [45]

Answer:

Step-by-step explanation:

its true

4 0
2 years ago
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
1 year ago
Once again I’m co fused lol
Leno4ka [110]

A to the middle one

B to the top one

C to the bottom one  

The top one is all real numbers because any number in the "l l" absolute brackets will come out to be positive, example: l-3l=3 and l3l=3. Thats going to be equal to and since the sign says "less than or equal to" that will work.

The middle one is only positive solutions because for 7x to be more than lxl it would need to be positive since the sign is "greater than"

The bottom one is none because the absolute of anything will always be more than a negative since the absolute is always positive. Never less or equal to a negative, always more.



7 0
3 years ago
BONUS!
Nitella [24]
The answer is gonna be 14
3 0
2 years ago
I NEED HELP!! And it doesn’t accept equal signs in the answer
miv72 [106K]
You just to factor the right side of the equation. The “y = ” is already on the left of the answer box. Hope this helps


Brainliest plz
7 0
2 years ago
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