now, you're asked to use it when ln(1.38), which is just another way of saying x = 1.38
so set x = 1.38 and see what "y" is
Current amount in account
P=36948.61
Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n
Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11
We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000
We can solve this by trial and error.
The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.
So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.
So it takes 15.00 years to reach the goal of 280000 years.
You are correct, the profit is modeled by:
-0.1t² + 6t + 67
We are also told that "t" is the number of years after 2010. So in 2016, the value of t will be 6. We substitute this into the equation we formed:
-0.1(6²) + 6(6) + 67
= 106.6 thousand dollars
We are to find the value of
First we need to find the inverse of f(x) . The inverse of
is
.
Steps to find inverse of f(x) are shown below in the image.
So
=
Therefore, the correct answer is option C
Answer:
Final answer is slope 
Step-by-step explanation:
Given equation is 
Now question says to find the slope.
Since given equation is a linear equation so we need to compare with slope intercept formula 
to get the value of slope m.
Since is not in that form so first let's rewrite it in y=mx+b form
Now comparing with y=mx+b, we get
Hence final answer is slope
