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3 years ago

7th grade help me please :))

Mathematics

1 answer:

MatroZZZ [7]3 years ago

5 0

Answer:

there are 4 terms, ,+4, +2, ,-7, and +6

Step-by-step explanation:

terns are like numbers, they can be positive or negative!

hope this helps:)) hheheeh

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Write a quadratic function f whose only zeros are -3 and -12

emmasim [6.3K]

Answer:

Step-by-step explanation:

f(x) = (x + 3)(x + 12)

f(x) = x^2 + 3x + 12x + 36

f(x) = x^2 + 15x + 36

3 0

2 years ago

Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur

Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel at the speed of light. You know that light can travel a distance of 5.88 x 10^12 miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

$9.3*10^7\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years$

This time is very small in years

Convert to minutes

$1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min$

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

$2.5*10^{13}\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years$

$4.25\ years< 5\ years$

therefore

The spaceship will get to Alpha Centaur in time

3 0

3 years ago

Solve for x (2x-8) (9x-10)

mars1129 [50]

Answer

x+3=17

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

PLS ANSWER ASAP!!!!!<br> Simplify 5^-4/5^3

Alekssandra [29.7K]

Answer:

None on the above.

Step-by-step explanation:

Here’s what I got:

1/5^-1.

3+(-4)=-1

5^-4/5^3 = 1/5^-1

5 0

2 years ago

an automobile 16 feet long overtakes a truck that is 28 feet long and is traveling 30 mph. At what rate must the automobile trav

Oduvanchick [21]

<h2>Automobile must travel at 96 mph to pass the truck in 4 seconds.</h2>

Step-by-step explanation:

Length of automobile = 16 feet = 4.88 m

Length of truck = 28 feet = 8.53 m

Speed of truck = 30 mph = 48 km/h = 13.33 m/s

Time in which automobile to pass truck = 4 s

Distance traveled by truck in 4 seconds = 4 x 13.33 = 53.33 m

Distance which need to cover by automobile in 4 seconds to pass truck is the sum of length of automobile, length of truck and distance traveled by truck in 4 seconds.

Distance which need to cover by automobile in 4 seconds = 4.88 + 8.53 + 53.33

Distance which need to cover by automobile in 4 seconds = 66.74 m

Distance = Speed x Time

66.74 = Speed x 4

Speed = 16.69 m/s = 60 km/h = 96 mph

Automobile must travel at 96 mph to pass the truck in 4 seconds.

8 0

3 years ago