Answer:
Perimeter: 52 Area: 181-16i?
Step-by-step explanation:
<u>Perimeter</u>
The formula for perimeter is 2l+2w, so you plug in the binomials they give you:
2(11-4i)+2(15+4i)
expand:
22-8i+30+8i
combine like terms (which cancels out 8i and -8i):
22+30=52
<u>Area</u>
"i" is not a real number and thus should not be part of the area here, meaning this answer as it is is wrong and I don't know how one would change that.
Here's what I did to get 181-16i, in any case:
The formula for area is l*w, so I plugged in the numbers:
(11-4i)(15+4i)
expanded:
165+44i-60i-16i*i
and combined like terms:
181-16i
*i is , so
=-1 and -1*-16=16.
Answer: Option 'd' is correct.
Step-by-step explanation:
Since we have given that
Number of hours of pop music = 3
Number of hours of classical music = 2
According to question, Every month onwards, the hours of pop music in her collection is 5% more than what she had the previous month. Her classical music does not change.
Rate of increment = 5% = 0.05
Let the number of months be 'x'.
So, our required function becomes,
Hence, Option 'd' is correct.
Answer:
The correct option is;
False
Step-by-step explanation:
The coefficient of x^k·y^(n-k) is nk, False
The kth coefficient of the binomial expansion, (x + y)ⁿ is
Where;
k = r - 1
r = The term in the series
For an example the expansion of (x + y)⁵, we have;
(x + y)⁵ = x⁵ + 5·x⁴·y + 10·x³·y² + 10·x²·y³ + 5·x·y⁴ + y⁵
The third term, (k = 3) coefficient is 10 while n×k = 3×5 = 15
Therefore, the coefficient of x^k·y^(n-k) for the expansion (x + y)ⁿ = not nk
Answer:
Area of the shaded region = 1.92 cm²
Step-by-step explanation:
From the picture attached,
Area of the shaded region = Area of the sector OMN - Area of the triangle OMN
Area of sector OMN =
Here, θ = Central angle of the sector
r = radius of the sector
Area of sector OMN =
= 15.708 square cm
Area of ΔOMN = 2(ΔOPN)
Area of ΔOPN =
Area of ΔOMN = OP × PN
In ΔOPN,
sin(25°) =
PN = ONsin(25°)
= 6sin(25°)
= 2.536 cm²
cos(25°) =
OP = ONcos(25°)
OP = 6cos(25°)
OP = 5.438 cm
Area of ΔOMN = 2.536 × 5.438
= 13.791 cm²
Area of the shaded region = 15.708 - 13.791 = 1.917 cm²
≈ 1.92 cm²
