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icang [17]
3 years ago
15

Please solve fast please ​

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

  1. 3/6 =1/2
  2. 5/6

pls give me brainliest plzzzzz

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The width of a rectangle is only 15% of its length. If the perimeter of the rectangle is 46, what is the length
sveta [45]

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20 units

Step-by-step explanation:

Let the length be x. According to the question,

  • Length = x
  • Width = 15% of the length

➝ Width = 15% of the length

➝ Width = 15/100x

➝ Width = 3/20x

We have the perimeter of the rectangle that is 46 units.

\longrightarrow \sf {Perimeter_{(Rec.)} = 2(L + W) } \\

\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{20x + 3x}{20} \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{23x}{20} \Bigg \rgroup } \\

\longrightarrow \sf {\dfrac{46}{2}=  \dfrac{23x}{20}} \\

\longrightarrow \sf {23=  \dfrac{23x}{20}} \\

\longrightarrow \sf {23 \times 20 = 23x} \\

\longrightarrow \sf {460= 23x} \\

\longrightarrow \sf {\cancel{\dfrac{460}{23}} = x} \\

\longrightarrow \underline{\boxed{ \bf {20\; units = x}}} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>rectang</u><u>le</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u> </u><u>units</u><u>.</u>

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