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mario62 [17]
3 years ago
7

What multiples to -35 but adds to 8

Mathematics
1 answer:
grandymaker [24]3 years ago
7 0
Factors of 35:
1 and 35
5 and 7

Bad break for you, you're going to have to find some other way to factor your quadratic equation. Try the quadratic formula.
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How do u solve 3= t + 11.5 - t ?
shepuryov [24]

11.5

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7 0
3 years ago
Madelynne hopped 12 times in 15 seconds.What is her speed in hops per minute?
BabaBlast [244]
60 seconds = 1 minute
60/15 = 4

12 hops in 15 seconds is the same as

4 * 12 hops in 4 * 15 seconds, or

48 hops in 60 seconds, and since 60 sec = 1 min, it equals

48 hops per minute.
7 0
4 years ago
8x10^30/2x10^12 in scientific notation?
4vir4ik [10]

Answer:

4*10^18

Step-by-step explanation:

Easier to think of it as the factors out front (8 / 2) = 4

and subtract the exponents 30 - 12 = 18

= 4*10 ^18

5 0
4 years ago
a table was listed $400 after discount.And the net price was $450.what is the rate discount and marked price?​
Rama09 [41]

Answer:

Your answer

Discount rate = 11.11%

Mark it as Brainlist. Follow me for more answer.

Step-by-step explanation:

5 0
4 years ago
Let f be a differentiable function such that f(1)=π and f'(x)=√x^3+6. what is the value of f(5)?
natali 33 [55]

The value of f(5) is 49.1

Step-by-step explanation:

To find f(x) from f'(x) use the integration

f(x) = ∫ f'(x)

1. Find The integration of f'(x) with the constant term

2. Substitute x by 1 and f(x) by π to find the constant term

3. Write the differential function f(x) and substitute x by 5 to find f(5)

∵ f'(x) = \sqrt{x^{3}} + 6

- Change the root to fraction power

∵ \sqrt{x^{3}} = x^{\frac{3}{2}}

∴ f'(x) = x^{\frac{3}{2}} + 6

∴ f(x) = ∫ x^{\frac{3}{2}} + 6

- In integration add the power by 1 and divide the coefficient by the

 new power and insert x with the constant term

∴ f(x) = \frac{x^{\frac{5}{2}}}{\frac{5}{2}} + 6x + c

- c is the constant of integration

∵ \frac{x^{\frac{5}{2}}}{\frac{5}{2}}=\frac{2}{5}x^{\frac{5}{2}}

∴ f(x) = \frac{2}{5} x^{\frac{5}{2}} + 6x + c

- To find c substitute x by 1 and f(x) by π

∴ π = \frac{2}{5} (1)^{\frac{5}{2}} + 6(1) + c

∴ π = \frac{2}{5} + 6 + c

∴ π = 6.4 + c

- Subtract 6.4 from both sides

∴ c = - 3.2584

∴ f(x) = \frac{2}{5} x^{\frac{5}{2}} + 6x - 3.2584

To find f(5) Substitute x by 5

∵ x = 5

∴ f(5) = \frac{2}{5} (5)^{\frac{5}{2}} + 6(5) - 3.2584

∴ f(5) = 49.1

The value of f(5) is 49.1

Learn more:

You can learn more about differentiation in brainly.com/question/4279146

#LearnwithBrainly

4 0
3 years ago
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