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kari74 [83]
2 years ago
11

Fill in the missing term in the equation

Mathematics
1 answer:
Y_Kistochka [10]2 years ago
6 0

Answer:

<u>x</u>

Step-by-step explanation:

Let's simplify the LHS so it can be equated to the RHS.

\frac{x}{x^{2} -4x+4} - \frac{x}{x^{2} -3x+2}

\frac{x}{(x-2)^{2} } - \frac{x}{(x-1)(x-2)}

\frac{x(x-1)-x(x-2)}{(x-2)^{2}(x-1)}

\frac{x^{2} -x-x^{2}+2x }{(x-2)^{2}(x-1)}

\frac{x}{(x-2)^{2}(x-1)}

Hence, the missing term in the numerator of the answer is <u>x</u>

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