Question

Fill in the missing term in the equation

Answer 1

Answer:

x

Step-by-step explanation:

Let's simplify the LHS so it can be equated to the RHS.

$\frac{x}{x^{2} -4x+4} - \frac{x}{x^{2} -3x+2}$

$\frac{x}{(x-2)^{2} } - \frac{x}{(x-1)(x-2)}$

$\frac{x(x-1)-x(x-2)}{(x-2)^{2}(x-1)}$

$\frac{x^{2} -x-x^{2}+2x }{(x-2)^{2}(x-1)}$

$\frac{x}{(x-2)^{2}(x-1)}$

Hence, the missing term in the numerator of the answer is x