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2 years ago

Find the least common multiple (LCM) for the pair of numbers. 20, 3 Need answers like now

Mathematics

1 answer:

Effectus [21]2 years ago

4 0

Step-by-step explanation:

A method for this would be the tree diagram

/. \

10 x 2 ( u circle 2,times with 1 will times into itself)

/ \. (nothing goes into 2)

5x2 (same goes for 5 and the rest)

5x2x2= 20

3. (cant times into itself)

so 2x5x3 = 30

LCM = 30

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An oil tanker can be emptied by the main pump in 5 hours. An auxiliary pump can empty the tanker in 7 hours. If the main pump is

r-ruslan [8.4K]

Answer:

so the answer will be 1

Step-by-step explanation:

An oil tanker can be emptied by the main pump in 5 hours.

An auxilary pump can empty the tanker in 14 hours.

If the main pump is started at 7pm, when should the auxilary pump be started

so that the tanker is emptied by 11pm?

Let t = no. of hrs to run the Aux pump

The main pump will run 4 hr (7 - 11 pm)

Let the completed job = 1; (an empty Tanker)

The shared work equation

4%2F5 + t%2F14 = 1

Multiply equation by 70 to get rid of the equation, results:

14(4) + 5t = 70

56 + 5t = 70

5t = 70 - 56

5t = 14

t = 14%2F5

t = 2.8 hrs to run the aux pump

2.8 hr = 2 + .8(60) = 2 hrs 48 min

Subtract 2:48 from 11:00 = 8:12 PM start the aux pump

;

Check solution

4/5 + 2.8/14 =

.8 + .2 = 1

6 0

2 years ago

Write in summation notation.

Ivahew [28]

If that is -2+1+4+13 I think it should be 16

3 0

2 years ago

if gabby wants to make a regular octagon with a side length of 20 inches of water , how much wire does she need?

EleoNora [17]

Answer:

160 inches

Step-by-step explanation:

An octagon has 8 sides;

20*8=160

4 0

2 years ago

Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

4 0

2 years ago

A game decreased in price by 2/3. After the reduction it was priced at £13. What was the original price of the game?

Archy [21]

Answer:

$x = 39$

Step-by-step explanation:

Based on the given conditions, write: $x=\frac{13}{1-\frac{2}{3}}$

Find common denominator and write numerators above common denominator: $x=\frac{\frac{13}{3-2} }{3}$

Calculate the sum or difference: $x=\frac{\frac{13}{1} }{3}$

Divide the fraction by multiplying its reciprocal: $x=13*3$

Calculate the product or quotient: $x=39$

Answer: $x=39$

5 0

2 years ago

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