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2 years ago

Pleasee help ill give brainliest

Mathematics

2 answers:

Free_Kalibri [48]2 years ago

7 0

Answer:

always increasing

Step-by-step explanation:

BigorU [14]2 years ago

6 0

B or Always increasing

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A medical equipment industry manufactures X-ray machines. The unit cost C (the cost in dollars to make each X-ray machine) depen

earnstyle [38]

Answer:

$11988

Step-by-step explanation:

Given that,

The unit cost is given by :

$C(x)=0.7x^2-462x+88218$

We need to find the minimum unit cost.

For minimum cost,

Put $\dfrac{dC}{dx}=0$

So,

$\dfrac{d}{dx}(0.7x^2-462x+88218)=0\\\\1.4x-462=0\\\\x=\dfrac{462}{1.4}\\\\x=330$

Put x = 330 in equation (1).

$C(330)=0.7(330)^2-462(330)+88218\\\\=\$11988$

So, the minimum unit cost is equal to $11988.

5 0

2 years ago

Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times

Elina [12.6K]

Answer:

The probability is $P(A') = 0.485$

Step-by-step explanation:

Let assume that the number of computer produced by factory C is k = 1

So From the question we are told that

The number produced by factory A is 4k = 4

The number produced by factory B is 7k = 7

The probability of defective computers from A is $P(A) = 0.04$

The probability of defective computers from B is $P(B) = 0.02$

The probability of defective computers from C is $P(C) = 0.03$

Now the probability of factory A producing a defective computer out of the 4 computers produced is

$P(a) = 4 * P(A)$

substituting values

$P(a) = 4 * 0.04$

$P(a) = 0.16$

The probability of factory B producing a defective computer out of the 7 computers produced is

$P(b) = 7 * P(B)$

substituting values

$P(b) = 7 * 0.02$

$P(b) = 0.14$

The probability of factory C producing a defective computer out of the 1 computer produced is

$P(c) = 1 * P(C)$

substituting values

$P(c) = 1 * 0.03$

$P(b) = 0.03$

So the probability that the a computer produced from the three factory will be defective is

$P(t) = P(a) + P(b) + P(c)$

substituting values

$P(t) = 0.16 + 0.14 + 0.03$

$P(t) = 0.33$

Now the probability that the defective computer is produced from factory A is

$P(A') = \frac{P(a)}{P(t)}$

$P(A') = \frac{ 0.16}{0.33}$

$P(A') = 0.485$

3 0

3 years ago

10. Un átomo de potasio tiene 19 protones en el núcleo y 20 neutrones. A partir de estos datos, a) ¿Cuál será su número atómico?

hram777 [196]

Answer:

translate this to English and I'll help!(:

6 0

2 years ago

Help pls lol

Kobotan [32]

Answer:

Options :

Step-by-step explanation:

1200m + 500 = 10700

5 0

3 years ago

Simplify: StartRoot 324 EndRoot 1. Write the prime factorization of the radicand. StartRoot 324 EndRoot = StartRoot 2 times 2 ti

Savatey [412]

Answer:

Step-by-step explanation:

To continue where you left off, ...

$\sqrt{2^2}\times\sqrt{3^2}\times\sqrt{3^2}=2\times 3\times 3=18$

The square root of 324 is 18.

3 0

3 years ago

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