The dipole measured for HI is 0.380 D. The bond distance is 161 pm. What is the percent ionic character of the HI bond?
1 answer:
Answer:
Percent ionic character of HI bond is 4.91%.
Explanation:
<h3>Given Data:</h3>Measured Dipole = 0.380D
bond distance = d = 161pm = 1.61*10^-8 cm
<h3>Calculation:</h3>% ionic character is determined by following equation:
% ionic= (dipole measured/dipole calculated)*100
Now,
(In above step 3*10^8 is multiplied to convert coulomb into esu)
As,
So,
Now we can % ionic character using above equation:
%ionic=(0.380D/7.728D)*100
% ionic character=4.91%
You might be interested in
<u>For NO3- molecule(fig.1)</u>
1. Bonds are created between elements with different electronegativity, most bonds would be polar. Bonds in NO3 are polar.
2. In the geometry of the molecule bond polarities cancel out each other (since it is a vector) so NO3- ion molecule is non polar
3. Nitrate (NO3-)ion geometry would be trigonal planar
<u>For CCl4 molecule(fig.2)</u>
1. Bonds are created between elements with different electronegativity, most bonds would be polar. Bonds in CCl4 are polar.
2. It is a completely symmetrical molecule.
3.Carbon is the centre of CCl4 have four covalent bonds and it has no lone pairs. They are all equidistant the C-Cl bond polarities cancel out. So CCl4 molecule is non polar
<u>For NH3 molecule(fig.3)</u>
1. Bonds are created between elements with different electronegativity, most bonds would be polar. Bonds in NH3 molecule are polar.
2. it has a pyramidal structure.
3. the individual N-H bond dipoles don't cancel out. This dipole moment for the molecule indicates that NH3 is a polar molecule
<u>For SF6 molecule(fig.4)</u>
1.F is more electronegative than S. So the bonds are polar.
2. The symmetry of the molecule is symmetrical so that the dipole moments of bonds cancel correspond so the molecule is non-polar.
3. it has octahedral structure
