It's not an element or a compound because it's not pure or something like oxygen... it is a homogeneous mixture like tea and sugar
Given in the problem is the mass of the liquid (500 grams) and the volume of the liquid (1000 ml = 1000 cm^3).
We can use these two givens to calculate the density of the liquid using the following rule:
density = mass / volume
density = 500 / 1000 = 0.5 grams / cm^3
Comparing the calculated density with the choices we have, we can deduce that the liquid is most likely to be propane with density 0.494 g / cm^3
Answer:
R=0.0438 Ω
Explicación:
1) Hallar el área o sección del conductor de cobre, usando esta fórmula:
A=π.r² (Pi x radio al cuadrado)
Debido a que conocemos el diámetro (1.5mm) su radio es la mitad de esto es decir 0.75mm, y lo sustituimos en la fórmula:
A=π.(0.75mm)²
A=π(0.5625mm²)
A=1.7671mm²
2) La resistividad del cobre es: rho = 0,0172 y la incluimos en la fórmula siguiente:
R=p
R=0,0172Ω x
Simplificamos:
R=
El resultado es:
R=0.0438 Ω
Explanation:
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