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Klio2033 [76]
3 years ago
6

Chemical equations must be properly balanced because chemical reactions follow the first law of thermodynamics.

Mathematics
1 answer:
True [87]3 years ago
7 0

I thinking it’s true. The law of conservation of matter has been satisfied. When the reactants and products of a chemical equation have the same number of atoms of all elements present, we say that an equation is balanced. All proper chemical equations are balanced.

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3k-2=10 whats the answer
kap26 [50]

Answer:

k = 4

Step-by-step explanation:

3k - 2 = 10

3k - 2 + 2 = 10 + 2     (adding 2 to both sides)

           3k = 12

        3k/3 = 12/3       (dividing both sides by 3)

             k = 4

Happy to help :)

4 0
3 years ago
SOMEONE PLEASE HELP ME BEFORE I FAIL
Viefleur [7K]

Answer:

4/40

Step-by-step explanation:

you can reduce this to 1/10

multiplying 4 by both 1 and 10 will give you the fraction 4/40 both can be divided by 4 and that's how it can reduce to the 1st fraction (1/10)

8 0
3 years ago
Determine the value of k
KATRIN_1 [288]

Answer:

\displaystyle k = 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Functions
  • Function Notation

<u>Algebra II</u>

  • Piecewise Functions<u> </u>

<u>Calculus</u>

  • Limits
  • Continuity

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Continuous at x = 2

\displaystyle f(x) = \left \{ {{2x^2 \ if \ x < 2} \atop {x + k \ if \ x \geq 2}} \right.

<u>Step 2: Solve for </u><em><u>k</u></em>

  1. Definition of Continuity:                                                                                   \displaystyle  \lim_{x \to 2^+} 2x^2 =  \lim_{x \to 2^-} x + k
  2. Evaluate limits:                                                                                                  \displaystyle 2(2)^2 =  2 + k
  3. Evaluate exponents:                                                                                         \displaystyle 2(4) =  2 + k
  4. Multiply:                                                                                                             \displaystyle 8 =  2 + k
  5. [Subtraction Property of Equality] Subtract 2 on both sides:                        \displaystyle 6 = k
  6. Rewrite:                                                                                                             \displaystyle k = 6

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Limits - Continuity

Book: College Calculus 10e

4 0
3 years ago
Read 2 more answers
Find the surface of the prism
natta225 [31]

Answer:

no se podrías resolverlo tu

6 0
3 years ago
4x-y=1 slope intercept form​
Semmy [17]

Answer:

y=4x-1

Step-by-step explanation:

4x-y=1

4x=y+1 then negative Y becomes positive after going to the other side of the equal sign.

4x-1=y the positive 1 becomes negative after going to the other side of the equal sign.

5 0
3 years ago
Read 2 more answers
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