Answer:
The correct option for this is C.) The mean and median age are more likely to be the same for the students in Math 1.
Step-by-step explanation:
i) The median age of the students is Math 1 is less than the median age of the students in Math 2.
This statement is NOT TRUE as the median age of students in Math 1 = median age of students in Math 2 = 19
ii) The mean and median age are most likely the same for both sets of data.
This statement is NOT TRUE. The mean age of students in Math 2 should be greater than mean age of students in Math 1.
iii) The mean and median age are more likely to be the same for the students in Math 1.
This statement is TRUE.
The answer would be 50 for the question 8 becuase u do the opposite which is 86 divided by 2 and then add seven
Answer:
1) 
2) ![\sqrt[3]{y^5}=y^{\frac{5}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E5%7D%3Dy%5E%7B%5Cfrac%7B5%7D%7B3%7D)
3) ![\sqrt[5]{a^{12}}=a^{\frac{12}{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Ba%5E%7B12%7D%7D%3Da%5E%7B%5Cfrac%7B12%7D%7B5%7D%20%7D)
4) ![\sqrt[4]{z^{9}}=z^\frac{9}{4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bz%5E%7B9%7D%7D%3Dz%5E%5Cfrac%7B9%7D%7B4%7D)
Step-by-step explanation:
1) 
We know that 
So,
2) ![\sqrt[3]{y^5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E5%7D)
We know that ![\sqrt[3]{x}=x^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B3%7D)
So,
3) ![\sqrt[5]{a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Ba%5E%7B12%7D%7D)
We know that ![\sqrt[5]{x}=x^{\frac{1}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B5%7D)
So,
4) ![\sqrt[4]{z^{9}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bz%5E%7B9%7D%7D)
We know that ![\sqrt[4]{x}=x^{\frac{1}{4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B4%7D)
So,
The correct answer is 'C'
If X = 2, and Y = 4:
2(2) + 3(4) - 2 - (8 + 1) = 5
4 + 12 - 2 - 9 = 5
16 - 2 - 9 = 5
14 - 9 = 5
= 5
(2) + 3(4) - 9 = 5
2 + 12 - 9 = 5
14 - 9 = 5
= 5
So, your answer would be 'C' X + 3Y - 9
