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2 years ago

Brainliest goes to whoever answers correctly and explains also if you want extra points answer my other questions

Mathematics

1 answer:

Paul [167]2 years ago

8 0

Answer:

in all cases x/100 is just a way to represent percentage. and since it's the same everywhere, it's not even relevant to decide wich option describes the context right

A) 80/140 is the portion that describes the book readers over all people surveyed

B) 31/63 just 63 people are relevant bc it's specified that we only consider beach travelers.

that also explains the 31, bc that's the number of beach travelers who'd like to watch a movie

C) 15/80 only 80 movie watchers in total, of whom 15 would prefer the city

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What does solve w mean

cestrela7 [59]

It means to most likely isolate the variable and you should have something like w= or a number =w

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2 years ago

Josh earned 15% extra points on his 40 point assignment, how many total points did he earn?

Liono4ka [1.6K]

Total points : 46
15% of 40 is 6
40 + 6 = 46
To double check:
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2 years ago

Please help me!!!!!

chubhunter [2.5K]

Answer:

y = - $\frac{2}{5}$ (x - 5)² + 7

Step-by-step explanation:

The equation of a quadratic in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (5, 7 ) , then

y = a(x - 5)² + 7

To find a substitute (10, - 3 ) into the equation

- 3 = a(10 - 5)² + 7 ( subtract 7 from both sides )

- 10 = 5²a = 25a ( divide both sides by 25 )

$\frac{-10}{25}$ = a , that is

a = - $\frac{2}{5}$

y = - $\frac{2}{5}$ (x - 5)² + 7 ← in vertex form

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2 years ago

Limit question: lim x-->pi ((e^sinx)-1)/(x-pi)

aleksandr82 [10.1K]

$\displaystyle\lim_{x\to\pi}\dfrac{e^{\sin x}-1}{x-\pi}$

Notice that if $f(x)=e^{\sin x}$ , then $f(\pi)=e^{\sin\pi}=e^0=1$ . Recall the definition of the derivative of a function $f(x)$ at a point $x=c$ :

$f'(c):=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}$

So the value of this limit is exactly the value of the derivative of $f(x)=e^{\sin x}$ at $x=\pi$ .

You have

$f'(x)=\cos x\,e^{\sin x}\implies f'(\pi)=\cos\pi\,e^{\sin\pi}=-1$

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