he divided by 2 instead of taking the square root so the actual answer should be 26 and for the second the 20 is across from the 90 so its suppose to be c
the answer should be 16
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
total distance might be 16
Step-by-step explanation:
|y2-y1/x2-x1|, plug it the numbers, if you got a negative number, its just positive since the equation is set to absolute value
A is incorrect - In decimal form, 7/5 is 1.4
B is incorrect - In decimal form, 7/4 is 1.75
D is incorrect - In decimal form, 7/2 is 3.5
The answer is C. 7/4; In decimal form, 7/4 is 2.33333333.... (this represents a terminating decimal)
