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Serga [27]
3 years ago
15

MA the segment bisector of RS Find the length of RS. The length of RS is?

Mathematics
1 answer:
frez [133]3 years ago
4 0

Answer:

pfp cute is that you

Step-by-step explanation:

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The cost of three tickets to a movie is at least $20. Select an inequality that represents the cost x (in dollars) of each ticke
SVETLANKA909090 [29]

Answer:

x\geq \$6.67

Step-by-step explanation:

Let

x------> the cost of each ticket

we know that

3x\geq 20 ----> inequality that represent the situation

solve for x

Divide by 3 both sides

x\geq 20/3

x\geq \$6.67

5 0
3 years ago
Someone Explain to me how 5. Is valid ???
vichka [17]

This is valid through the law of syllogism. If you swap lines 1 and 2, then you'll have this argument:

If I step on a beehive, then I will get stung.

If I get stung by a bee, then it will hurt.

Therefore, if I step on a beehive, then it will hurt

------------------

So it's like connecting a chain together. Point A (stepping on the hive), leads to point B (getting stung), which leads to point C (getting hurt). We can take a shortcut to bypass point B to jump from A to C in one step. Check out the attached image for a visual of what I'm referring to.

6 0
3 years ago
Find the least 2-digit whole number N so that the sum 2^9+2^4+N is a perfect square.
oksano4ka [1.4K]

Answer:

N=48

Step-by-step explanation:

2^9+2^4+48=576

576 is a perfect square

3 0
2 years ago
0.12 word form decimal
7nadin3 [17]

Answer:

0.12=zero point one two

Step-by-step explanation:

6 0
3 years ago
Find the missing part.
sveta [45]

Answer:

The answer is a = \frac{15}{4}

Step-by-step explanation:

We have to:

cos(\theta) = \frac{adjacent\ side}{hypotenuse}

So, if we take the 60 degree angle of the smallest triangle, we have to:

cos(60) = \frac{a}{x}

We do not know x. But if we take the sine of the angle of 30 degrees and the main triangle we have:

sin(30) = \frac{x}{15}\\\\x =\frac{15}{2}

Then:

cos(60) = \frac{a}{\frac{15}{2}}

a = cos(60)\frac{15}{2}

a = \frac{15}{4}

7 0
2 years ago
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