Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)
first factor into (x-r1)(x-r2)... form
p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2
so
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real
baseically
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
The answer is A.50 just take the test. and was write
Answer:
y = -.5x -.5
Step-by-step explanation:
All you do is plug in the x and y in the point to the equation, y = mx + b. Since the coordinate is (5, -3), this in the equation would look like -3 = -.5(5) +b. (all you need to find is the y-intercept, or b.) Solve it out to get -3 = -2.5 + b. Add 2.5 to each side of the equation, you're left with b = -.5. Now, put that back into the original equation, and get y = -.5x -.5. I think this is right, you can go back through and check once more if you'd like.
Answer:
ιт ιѕ 11/10
Step-by-step explanation:
αℓℓ υ ∂σ ιѕ fℓιρ тнє fяα¢тισи ιѕ αяσυи∂ αи∂ тнєяє уα gσ
нσρє ι ¢συℓ∂ нєℓρ уσυ συт тσ∂αу!!!!!!!!
Answer:13
Step-by-step explanation:
11+2=13
