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3 years ago

Mrs. Watanabe is choosing a cell phone plan. One plan costs $35 a month and includes 450 minutes. The charge for each minute

Mathematics

1 answer:

sertanlavr [38]3 years ago

6 0

Answer:

this is only a statement with no question so I'm just assuming the question here:

It would be cheaper to buy the $$35/month plan if he uses under 575 min/month and cheaper to buy the $55 plan if using over 575 min/month

Step-by-step explanation:

$35 + x$0.16 = $55

-35. -35

_________________

x$0.16 = $20

÷ 0.16. ÷0.16

______________

x = 125 min

450 + 125 = 575 min

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The admission fee for a charity event is $7 for children and $10 for adults. The event was attended by 700 people and the total

Hitman42 [59]

X = 7
y = 10
x + y = 700
7x + 10y = 6400

10x + 10y = 7000
(-) 7x + 10y = 6400
______________
3x = 600
x = 200

200 + y = 700
y = 500

3 0

3 years ago

Kyle is creating a frame for a model car. He begins by piecing two rods together, as shown in the diagram. Justify why ZAEC is a

Licemer1 [7]

I think it’s d because that’s where the z would come from with the AEC right angle.

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3 years ago

Please help! acellus

ch4aika [34]

Answer:

The number that belongs in the green box is equal to 909.

General Formulas and Concepts:
Algebra I

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] Pythagorean Theorem:
$\displaystyle a^2 + b^2 = c^2$

a is a leg
b is another leg
c is the hypotenuse

Step-by-step explanation:

Step 1: Define

Identify given variables.

a = 30

b = 3

c = x

Step 2: Find x

Let's solve for the general equation that allows us to find the hypotenuse:

[Pythagorean Theorem] Square root both sides [Equality Property]:
$\displaystyle \begin{aligned}a^2 + b^2 = c^2 \rightarrow c = \sqrt{a^2 + b^2}\end{aligned}$

Now that we have the formula to solve for the hypotenuse, let's figure out what x is equal to:

[Equation] Substitute in variables:
$\displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2}\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2} \\& = \boxed{ \sqrt{909} } \\\end{aligned}$

∴ the hypotenuse length x is equal to √909 and the number under the square root, our answer, is equal to 909.

___

Learn more about Trigonometry: brainly.com/question/27707750

___

Topic: Trigonometry

3 0

2 years ago

Which system of equations can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x?

Sveta_85 [38]

$^{(1)}\ \ 4x^5-12x^4+6x=5x^3-2x\ \ ^{(2)}\\\\ \left\{\begin{array}{ccc}y=4x^5-12x^4+6x\ \ \ ^{(1)}\\y=5x^3-2x\ \ \ ^{(2)}\end{array}\right$

Answer: system nr 4.

7 0

3 years ago

If y = 8 cm, what is the area of the blue section of this shape?

Ivahew [28]

Answer:

56 cm squared

Step-by-step explanation:

First things first: Cop one triangle off the rectangle, and attach it to the other one, so the shape looks like a L

Now I can actually solve this:

The left side is 8 cm (because y = 8 cm)

The top is 10 cm

The middle is 6 cm

The inside left is 3 cm

And the very bottom is 2 cm

First, we'll solve for the newly constructed rectangle: 3 x 2. That equals 6.

Next, solve for the longer rectangle: 10 x 5. That's 50.

Now, add the two areas, and we get 56. So the area of the whole thing is 56 cm squared.

(Please keep in mind that I could be wrong, so double check it for me, thanks!)

7 0

3 years ago