Dominio:
(−∞,∞),{x|x∈R}
Rango:
(−∞,∞),{y|y∈R}
Answer:
Area = (36π - 12πx + x²π) mm²
Step-by-step explanation:
Given that,
radius of lense = 6mm
Length from outer layer of pupil to lense = x mm
Radius of pupil = 6 - x mm
<h3>
Formula to calculate area of pupil</h3><h3>
Area = π r²</h3>
<em> where r is radius of pupil</em>
Area = π (6 -x)²
Area = π (6² -2(6)(x) + x²)
Area = π (36 -12x +x²)
Area = (36π - 12πx + x²π) mm²
So, the polynomial in standard form that represent the area of pupil in terms of π = (36π - 12πx + x²π) mm²
Answer:
I'm pretty sure the answer is d,(When both angle KMQ and MNS are equal to angle PMN, the angles KMQ and MNS are congruent.)
Step-by-step explanation:
I had this question on my practice exam for my midterm.
