C: Moved down and to the left
Answer:
1) (c)∠ G = 34°
2) (a) x = 33°
3) (d) The perpendicular segments are JM, KL, PQ AND NR.
Step-by-step explanation:
Here in the given questions:
1) p II r
⇒ ∠ G = 34° (ALTERNATE EXTERIOR ANGLES)
Hence, the measure of ∠ G = 34°
2) In the given triangle:
The measure of exterior angle is always the sum of interior opposite angles.
⇒ Here, x + 72° = 105°
or, x = 105° - 72° = 33° , or x = 33°
3) The given plane in the cube is JKPN
The segments which have J , K , P and N as their one vertex are perpendicular to the given plane.
Hence, the segments are JM, KL, PQ AND NR.
I’m thinking 58.45? if that makes sense
Answer:
No solution
Step-by-step explanation:
6X - 3Y = -9--------------(1)
- 2 X +Y= 5---------------(2)
from equation two,
Y = 5+2X------------------(3)
substitute equation (3) into equation (1)
6X-3(5+2X)= -9
opening bracket
6X-15-6X= -9
6X- 6X = -9+15
0 = 6
<h2>therefore the answer is no solution</h2>
Answer:
b = 26°
Step-by-step explanation:
a ; b = complementary =>
a + b = 90° } => b = 90° - 64° = 26°
a = 64°