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mixas84 [53]
3 years ago
6

Fill in the blank. Given below, you can conclude that OD is congruent to _______.

Mathematics
1 answer:
Triss [41]3 years ago
5 0

Answer:

c

Step-by-step explanation:

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Worth 10 points please help me ASAP
Nitella [24]
(2,-2) would be the answer I think
8 0
2 years ago
2х + Зу = 3 y = 8 – 3х​
GaryK [48]

Answer: Point form: ( 3 , -1 )

              Equation form: X= 3 and Y= -1

Step-by-step explanation:

6 0
2 years ago
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
3 years ago
Read 2 more answers
The odds that you will pick a heart from a standard deck of 52 cards is 13:39.
podryga [215]
Not exactly sure but I think it's false hope this helps
3 0
3 years ago
In a relay race, the probability of the galaxy team winning is 22%. in another unrelated relay race, the probability of the kome
lina2011 [118]
We know that
<span>the probability of the Galaxy team winning is 22%------> 0.22
</span>the probability of the Galaxy team losing is 100%-22%----> 78%-----> 0.78

<span>the probability of the Komets team winning is 47%------> 0.47
</span>the probability of the Komets team losing is 100%-47%----> 53%-----> 0.53

therefore
<span>the probability of the comets losing their race and the galaxy winning theirs is
0.53*0.22=0.1166------> 11.66%

the answer is
11.66%</span>
4 0
3 years ago
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