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3 years ago

What is the range of these wages 245,140,525,163,195,174,140

Mathematics

1 answer:

Veronika [31]3 years ago

3 0

The range is about 226

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Which decimal is equivalent to 13/11

TiliK225 [7]

Answer:

1.18 is the answer but if u want to round u have the answer as 1.20=1.2

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3 years ago

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Samantha wants to use her savings of 1150 to buy shirts and watches for her family. The total price of the shirt she bought was

ioda

Answer-

The maximum number of watches that Samantha come by with her savings is 10.

Solution-

The amount of money Samantha has in her savings account = $1150

She wants to buy shirts and watches.

Cost of one shirt = $84

Cost of each watch = $99

Let she can buy maximum of x watches, so the net price of the watches is $99x.

Then,

$\Rightarrow 99x+84=1150\\\\\Rightarrow 99x=1150-84\\\\\Rightarrow 99x=1066\\\\\Rightarrow x=\dfrac{1066}{99}\\\\\Rightarrow x=10.77$

As the number of watches can not be in fraction, so at most she can buy 10 watches.

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3 years ago

What is 5\9 as a decimal

Eva8 [605]

Answer:

0. 5 the hyphen is over the 5 btw

Step-by-step explanation:

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2 years ago

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there are 30 major league baseball (MLB) teames and 32 National football League (NFL) teams. The expanded roster for MLB teams i

maria [59]

40 players multiplied by 30 teams = 1,200 players in the MLB
53 players multiplied by 32 teams = 1,696 players in the NFL.
1,696 - 1,200 = 496

There are 496 more players in the NFL then in the MLB.

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2 years ago

Find 2 common angles that sum to (17pi/12) 2. Evaluate tan(17pi/12) using the sum identity for tangent.

Dmitry [639]

Note that
$\frac{17 \pi }{12} = \frac{3 \pi }{12} + \frac{14 \pi }{12} = \frac{ \pi }{4} + \frac{7 \pi }{6}$

Note that
$x= \frac{ \pi }{4}:\,\, sin(x) =cos(x)= \frac{1}{ \sqrt{2} },\,tan(x)=1\\x= \frac{7 \pi }{6} :\,\,sin(x)=- \frac{1}{2} ,\,\,cos(x)=- \frac{ \sqrt{3} }{2} ,\,\,tan(x)= \frac{1}{ \sqrt{3} }$

Use the identity
$tan(x+y)= \frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

Therefore
$tan( \frac{17 \pi }{12} )= \frac{1+ \frac{1}{ \sqrt{3} } }{1- \frac{1}{ \sqrt{3} } } = \frac{ \sqrt{3}+1 }{ \sqrt{3}-1} = \frac{( \sqrt{3}+1 )^{2}}{( \sqrt{3}-1 )( \sqrt{3}+1 )} = \frac{3+1+2 \sqrt{3}}{3-1} =2+ \sqrt{3}$

Answer: 2 + √3

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3 years ago