Hello!
hint: we can rewrite your function as below:
<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π =
=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)
</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:
<span>"4P=π"
Hope this Helps! Have A Wonderful Day! :)</span>
Answer:
2t+2u+2v+4w
Step-by-step explanation:
Add up all of the terms
Answer:
The result of the integral is:
Step-by-step explanation:
We are given the following integral:
Trigonometric substitution:
We have the term in the following format: , in which a = 3.
In this case, the substitution is given by:
So
In this question:
So
We have the following trigonometric identity:
So
Replacing into the integral:
Coming back to x:
We have that:
So
Applying the arcsine(inverse sine) function to both sides, we get that:
The result of the integral is:
The domain tells you about the independent variable, number of payments made. So the inequality should be
smallest number of payments made ≤ variable representing payments ≤ largest number of payments made.
The smallest number of payments is 0 and the largest is 8, so you'll have
<span><span>
0≤variable≤8</span></span>