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Maurinko [17]
3 years ago
12

Please can someone help thank you

Mathematics
1 answer:
Nitella [24]3 years ago
5 0

Answer:

it would be 36-45 and 56-64

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Two-thirds of a class are boys. If there are 12 boys, then<br> how many girls are in the class?
son4ous [18]

Step-by-step explanation:

so 2/3 OF the class are boys...

***REMEMBER IN MATHEMATICS, ^OF^ IS USED TO SAY MULTPLICATION***

so 2/3 OF class(x) are boys and there are 12 boys...

so 2/3 * x = 12

12 / (2/3) = x

to solve use the Keep, Change, Flip method

Keep 12, change / to multiplication, flip 2/3 to 3/2

it becomes 12 * 3/2 and to solve easier 12 is same thing as 12/1

12/1 * 3/2

Multiply across (numerator by numerator and denominator by denominator)

(12*3) / (1*2) = 36 / 2

Simplify

18

So the class has 18 students, and 2/3 of boys (12 of the students)

we can solve for how many girls are in the class

Depending on how your teacher wants to see the work:

either 18 - 12 = 6

or 1/3 * 18 which we rewrite as 1/3 * 18/1 = (1*18)/(3*1) which is 18/3... simplified it is  6

There are 6 girls in the class.

Hope this helps! :)

6 0
3 years ago
What is the value of x? 45° 2 (2x - 5) &gt; n​
Vladimir [108]

Answer:

70 degrees

Step-by-step explanation:

Find the diagram attached

The sum of the angles is supplementary that is

45 + 2x- 5 = 180

2x + 40 = 180

2x = 180 - 40

2x = 140

x = 140/2

x = 70

Hence the value of x is 70 degrees

4 0
3 years ago
Consider the following graph
Ksenya-84 [330]
Part C : is the answer
7 0
3 years ago
Someone ask me to solve this.
Semenov [28]
X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 ----->  3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

 3k +4h =4          ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4  or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4  , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3 

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .




6 0
3 years ago
Julio caught 3 fish weighing a total of 23 1/2 pounds. One fish weighed 9 5/8 pounds and another weighed 6 1/4 pounds. How much
Airida [17]
So we need to know what 23 1/2 + 9 5/8 + 6 1/4 is.
first, we need to make them into equivalent fraction. 
so...
23 1/2 can be 23 4/8
9 5/8 and
6 1/4 can be 6 2/8
let's add the whole numbers.
23 + 9 + 6 = 38
4/8 + 5/8 + 2/8 = 11/8 = 1 3/8
so 38 + 1 3/8 is 39 3/8
the answer is 39 3/8 pounds

4 0
3 years ago
Read 2 more answers
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