Answer: First box 44, second box 77 and third box 80❤️
Step-by-step explanation:
10 in, 24 in, and 26 in. By the Converse of the Pythagorean Theorem, the lengths must satisfy the equation c² = a² + b². Let 26 = hypotenuse and 10 and 24 the legs of the triangle.
26² = 10² + 24²
676 = 100 + 576
676 = 676.
Yes, they can be lengths of a right triangle.
Answer:
h=6
Step-by-step explanation:
h/8=12/16
16h=96
h=6
Answer:
a = 3, -3
Step-by-step explanation:
Multiply (a+3)/(a+3) to 2/(a-3) and multiply (a-3)/(a-3) to 2/(a+3) to get:
2(a+3)/(a-3) and 2(a-3)/(a+3) which equals (2a+6)/(a^2-9) and (2a-6)/(a^2-9)
add those two together to get (4a)/(a^2-9) which is equal to a/(a^2-9) on the other side. Cross multiply to get 4a^3 - 36a = a^3 - 9a, add/subtract like terms and you get a = 3 or -3
Answer:
A = 222 units^2
Step-by-step explanation:
To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:
(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.
The area of this trapezoid is
A = (average vertical length)(width), which here is:
(21 + 16) units
A = --------------------- * (12 units), which simplifies to:
2
A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2
