All categories

3 years ago

Help me order the side from shortest to longest

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

4 0

Answer:

AC BA BC shortest to longest.

Step-by-step explanation:

All triangles have 180o in their interior angles. So A + B + C = 180

5x - 4 + 2x + 3 + 3x - 9 = 180 Combine the like terms on the left.

10x - 10 = 180 Add 10 to both sides

10x - 10 + 10 = 180 + 10

10x = 190

x = 190/10

x = 19

So <A = 5x - 4 = 91

<B = 2x + 3 = 41

Total 180

So the largest Line is opposite 91 and it is BC

The Middle sides line is opposite 48 and it is BA

The smallest line is opposite 41 and it is AC

AC BA BC shortest to longest.

svet-max [94.6K]3 years ago

3 0

Answer:

Step-by-step explanation:

AB BC AC

(I’m not sure, If Im wrong let me knoww ❤️❤️)

You might be interested in

Use the equation tool to complete the table.<br> y = 120 + 18(x)

Ira Lisetskai [31]

Answer:

x2 +2x−xy when x = 250 and y = −120 ... sic Algebra: Patterns and Equations (13:18)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

For the function f(x)=(x+6)^3, rind f^-1(x)

qaws [65]

Answer:

$f^{-1}(x)=\sqrt[3]{x}-6$

Step-by-step explanation:

$f(x)=(x+6)^3$

$y=(x+6)^3$

$x=(y+6)^3$

$\sqrt[3]{x}=y+6$

$\sqrt[3]{x}-6=y$

5 0

3 years ago

Find the ordered pairs for the x- and y-intercepts of the equation 3x - 2y =18

Len [333]

X-int:let y=0
3x-2(0)=18
3x=18
divide both sides by 3
therefore x=6
y-int:let x=0
3(0)-2y=18
-2y=18
we divide both side by -2
therefore y=-9

5 0

3 years ago

Which of the following is equal to the rational expression when x does not equal 3 or 1 x^2-9/(x-1)(x-3)

yuradex [85]

Answer:

b. $\frac{x+3}{x-1}$

Step-by-step explanation:

Given expression is:

$\frac{x^{2}-9 }{(x-1)(x-3)}$

Let us factorize the numerator using the formula:

$a^{2} -b^{2} =(a+b)(a-b)$

$\frac{(x+3)(x-3)}{(x-1)(x-3)}$

Since x ≠ 3, let us cancel the common factor x - 3 in the numerator and in the denominator.

So, $\frac{x^{2}-9 }{(x-1)(x-3)} =\frac{x+3}{x-1}$

7 0

4 years ago

Determine the maximized area of a rectangle that has a perimeter equal to 56m by creating and solving a quadratic equation. What

sveticcg [70]

Answer:

Area of rectangle = $196\,m^2$

Length of rectangle = 14 m

Width of rectangle = 14 m

Step-by-step explanation:

Given:

Perimeter of rectangle is 56 m

To find: the maximized area of a rectangle and the length and width

Solution:

A function $y=f(x)$ has a point of maxima at $x=x_0$ if $f''(x_0)$

Let x, y denotes length and width of the rectangle.

Perimeter of rectangle = 2( length + width )

$=2(x+y)$

Also, perimeter of rectangle is equal to 56 m.

So,

$56=2(x+y)\\x+y=28\\y=28-x$

Let A denotes area of rectangle.

A = length × width

$A=xy\\=x(28-x)\\=28x-x^2$

Differentiate with respect to x

$\frac{dA}{dx}=28-2x$

Put $\frac{dA}{dx}=0$

$28-2x=0\\2x=28\\x=14$

Also,

$\frac{d^2A}{dx^2}=-2$

At x = 14, $\frac{d^2A}{dx^2}=-2$

So, x = 14 is a point of maxima

So,

$y=28-x=28-14=14$

Area of rectangle:

$A=xy=14(14)=196\,m^2$

Length of rectangle = 14 m

Width of rectangle = 14 m

5 0

3 years ago